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Draw a table for the mapping defined by the rule x → 2x² - 2 on the domain -1, 0, 1, 2, 3, 4.

Mathematics

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1. (a) Copy and complete the table.

NumberRound to the nearest tenthsRound to the nearest hundredthsRound to the nearest thousandths
486.3685486.4486.37486.369
0.0605380.10.060.061
2.213255352.22.212.213

1. (b) Solve the following:

  • a) Between two supplementary angles, one angle is twice the other. Find the size of the larger angle.
  1. Let the two supplementary angles be xx and yy.

    Since they are supplementary, their sum is 180∘180^\circ. x+y=180∘ x + y = 180^\circ

  2. One angle is twice the other, so let y=2xy = 2x.

    Substitute this into the equation. x+2x=180∘ x + 2x = 180^\circ 3x=180∘ 3x = 180^\circ

  3. Solve for xx.

    $$
    x = \frac{180^\circ}{3} = 60^\circ
    $$
    
  4. Find the other angle, yy.

    $$
    y = 2x = 2(60^\circ) = 120^\circ
    $$
    The larger angle is $\boxed{\text{}120^\circ\text{}}$
    
    • b) If one part of a complementary angle is 45∘45^\circ, what is the value of the other side?
  5. Let the two complementary angles be AA and BB.

    Since they are complementary, their sum is 90∘90^\circ. A+B=90∘ A + B = 90^\circ

  6. Given one angle is 45∘45^\circ, substitute A=45∘A = 45^\circ.

    $$
    45^\circ + B = 90^\circ
    $$
    
  7. Solve for BB.

    $$
    B = 90^\circ - 45^\circ = 45^\circ
    $$
    The value of the other angle is $\boxed{\text{}45^\circ\text{}}$
    

    1. (c) Agogo standing at point P on a school soccer field, moved 20 steps due east to a point Q and then moved 10 steps due south to a point R. Illustrate the movement of Agogo with a diagram.
    A diagram illustrating the movement would show:

    • A starting point labeled P.
    • An arrow pointing right (East) from P, labeled "20 steps", ending at point Q.
    • An arrow pointing down (South) from Q, labeled "10 steps", ending at point R.

    2. (a) Draw a table for the mapping defined by the rule x→2x2−2x \rightarrow 2x^2 - 2 on the domain {−1,0,1,2,3,4}\{-1, 0, 1, 2, 3, 4\}.

    xxy=2x2−2y = 2x^2 - 2
    −1-12(−1)2−2=2(1)−2=02(-1)^2 - 2 = 2(1) - 2 = 0
    02(0)2−2=2(0)−2=−22(0)^2 - 2 = 2(0) - 2 = -2
    12(1)2−2=2(1)−2=02(1)^2 - 2 = 2(1) - 2 = 0
    22(2)2−2=2(4)−2=62(2)^2 - 2 = 2(4) - 2 = 6
    32(3)2−2=2(9)−2=162(3)^2 - 2 = 2(9) - 2 = 16
    42(4)2−2=2(16)−2=302(4)^2 - 2 = 2(16) - 2 = 30

    2. (b) Simplify the following algebraic expressions:

    • i) 3y+2x(x+y)−x2+y3y + 2x(x+y) - x^2 + y
  8. Distribute $2x$ into the parenthesis.

    $$
    3y + 2x^2 + 2xy - x^2 + y
    $$
    
  9. Group like terms.

    $$
    (3y + y) + (2x^2 - x^2) + 2xy
    $$
    
  10. Combine like terms.

    $$
    \boxed{\text{}4y + x^2 + 2xy\text{}}
    $$
    
    • ii) 2a−2a(a+2x)+42a - 2a(a+2x) + 4
  11. Distribute −2a-2a into the parenthesis.

    $$
    2a - 2a^2 - 4ax + 4
    $$
    
  12. The terms are already simplified as there are no like terms to combine.

    $$
    \boxed{\text{}2a - 2a^2 - 4ax + 4\text{}}
    $$
    

    2. (c) The mean (average) of five consecutive natural numbers is 11. Find the first of these numbers.

  13. Let the first natural number be nn.

    The five consecutive natural numbers are n,n+1,n+2,n+3,n+4n, n+1, n+2, n+3, n+4.

  14. Calculate their sum.

    Sum=n+(n+1)+(n+2)+(n+3)+(n+4)=5n+10\text{Sum} = n + (n+1) + (n+2) + (n+3) + (n+4) = 5n + 10
  15. The mean is the sum divided by the count (5).

    Set this equal to 11.

    5n+105=11\frac{5n + 10}{5} = 11
  16. Simplify the equation.

    n+2=11n + 2 = 11
  17. Solve for nn.

    n=11−2=9n = 11 - 2 = 9

    The first of these numbers is 9\boxed{\text{}9\text{}}

    3. Complete the table.

    First, calculate the total frequency:
    Total Frequency = 8+7+13+15+5=488 + 7 + 13 + 15 + 5 = 48.

    Now, calculate the Angle of Sector for each brand using the formula: Angle=(FrequencyTotal Frequency)×360∘\text{Angle} = \left(\frac{\text{Frequency}}{\text{Total Frequency}}\right) \times 360^\circ.

    • Nokia: (848)×360∘=60∘\left(\frac{8}{48}\right) \times 360^\circ = 60^\circ
    • Samsung: (748)×360∘=52.5∘\left(\frac{7}{48}\right) \times 360^\circ = 52.5^\circ
    • Techno: (1348)×360∘=97.5∘\left(\frac{13}{48}\right) \times 360^\circ = 97.5^\circ
    • iPhone: (1548)×360∘=112.5∘\left(\frac{15}{48}\right) \times 360^\circ = 112.5^\circ
    • LG: (548)×360∘=37.5∘\left(\frac{5}{48}\right) \times 360^\circ = 37.5^\circ
    Phone brandTallyFrequencyAngle of sector
    Nokia860∘60^\circ
    Samsung752.5∘52.5^\circ
    Techno1397.5∘97.5^\circ
    iPhone15112.5∘112.5^\circ
    LG537.5∘37.5^\circ
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