Find each of the following number in their simplest form of module 5. 23 34 46

To find the simplest form modulo 5, we need to find the remainder when each number is divided by 5.

For 23:

$$23 \div 5 = 4 \text{ with a remainder of } 3$$

So, $23 \equiv 3 \pmod{5}$.
The simplest form is $\boxed{\text{3}}$

For 34:

$$34 \div 5 = 6 \text{ with a remainder of } 4$$

So, $34 \equiv 4 \pmod{5}$.
The simplest form is $\boxed{\text{4}}$

For 46:

$$46 \div 5 = 9 \text{ with a remainder of } 1$$

So, $46 \equiv 1 \pmod{5}$.
The simplest form is $\boxed{\text{1}}$