Solve the equation Cos(θ - 75°) = (√6 − √2) / 4 for 0° ≤ θ ≤ 360°

This is a known exact value for $\cos(75^\circ)$ or $\sin(15^\circ)$.
So, we have:

If $\cos A = \cos B$, then $A = \pm B + 360^\circ n$, where $n$ is an integer.
So, we have two cases:
Case 1: $\theta - 75^\circ = 75^\circ + 360^\circ n$
Case 2: $\theta - 75^\circ = -75^\circ + 360^\circ n$

For $n=0$, $\theta = 150^\circ$. This is within the range $0^\circ \leq \theta \leq 360^\circ$.
For $n=1$, $\theta = 150^\circ + 360^\circ = 510^\circ$, which is outside the range.
For $n=-1$, $\theta = 150^\circ - 360^\circ = -210^\circ$, which is outside the range.

For $n=0$, $\theta = 0^\circ$. This is within the range $0^\circ \leq \theta \leq 360^\circ$.
For $n=1$, $\theta = 360^\circ$. This is within the range $0^\circ \leq \theta \leq 360^\circ$.
For $n=2$, $\theta = 720^\circ$, which is outside the range.
For $n=-1$, $\theta = -360^\circ$, which is outside the range.

The solutions are $0^\circ$, $150^\circ$, and $360^\circ$.

The final answer is $\theta = 0^\circ, 150^\circ, 360^\circ$.