Solve the equation sin(5/2) θ = 1/2 for 0° ≤ θ ≤ 180°.

Step 1: Given equation
$\sin \theta = \frac{\sqrt{3}}{2}$

Step 2: Sine is positive in Quadrant I and Quadrant II.
Reference angle $\alpha$ satisfies $\sin \alpha = \frac{\sqrt{3}}{2}$.
Standard value: $\alpha = 60^\circ$.

Step 3: Quadrant I solution
$\theta = \alpha = 60^\circ$

Step 4: Quadrant II solution
Principal value is $180^\circ$.
$\theta = 180^\circ - \alpha = 180^\circ - 60^\circ = 120^\circ$

Step 5: Verify solutions in $[0^\circ, 360^\circ]$
$\sin 60^\circ = \frac{\sqrt{3}}{2}$ and $\sin 120^\circ = \frac{\sqrt{3}}{2}$.
No other solutions.

Final answers: $\theta = 60^\circ, 120^\circ$
$\boxed{\theta = 60^\circ, 120^\circ}$