Find the values of θ between 0° and 360° satisfying the equation 5 sin θ = -4.

Mathematics
Find the values of θ between 0° and 360° satisfying the equation 5 sin θ = -4.

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Answer

100πcm3100\pi cm^{3}

Step 1: Find the height hh using the slant height formula.

l2=r2+h2l^{2} = r^{2} + h^{2}

Substitute r=5r = 5 cm and l=13l = 13 cm:

132=52+h213^{2} = 5^{2} + h^{2} 169=25+h2169 = 25 + h^{2} h2=16925h^{2} = 169 - 25 h2=144h^{2} = 144 h=144h = \sqrt{144} h=12cmh = 12 cm

Step 2: Find the volume VV of the cone.

V=13πr2hV = \frac{1}{3} \pi r^{2} h

Substitute r=5r = 5 cm and h=12h = 12 cm:

V=13π(5)2(12)V = \frac{1}{3} \pi (5)^{2} (12) V=13π(25)(12)V = \frac{1}{3} \pi (25) (12) V=13π(300)V = \frac{1}{3} \pi (300) V=100πcm3V = 100 \pi cm^{3}

100\pi \text{ cm^{3}}

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Quick Answer

Find the height h using the slant height formula. l^2 = r^2 + h^2 Substitute r = 5 cm and l = 13 cm: 13^2 = 5^2 + h^2 169 = 25 + h^2 h^2 = 169 - 25 h^2 = 144 h = sqrt(144) h = 12 cm Step 2: Find the volume V of the cone.

Find the values of θ between 0° and 360° satisfying the equation 5 sin θ = -4.
Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI Answer
Step 1: Find the height h using the slant height formula. l^2 = r^2 + h^2 Substitute r = 5 cm and l = 13 cm: 13^2 = 5^2 + h^2 169 = 25 + h^2 h^2 = 169 - 25 h^2 = 144 h = sqrt(144) h = 12 cm Step 2: Find the volume V of the cone. V = (1)/(3) r^2 h Substitute r = 5 cm and h = 12 cm: V = (1)/(3) (5)^2 (12) V = (1)/(3) (25) (12) V = (1)/(3) (300) V = 100 cm^3 100 cm^3