Find the values of θ between 0° and 360° satisfying the equation 5 sin θ = -4.

$$l^{2} = r^{2} + h^{2}$$

Substitute $r = 5$ cm and $l = 13$ cm:

$$13^{2} = 5^{2} + h^{2}$$ $$169 = 25 + h^{2}$$ $$h^{2} = 169 - 25$$ $$h^{2} = 144$$ $$h = \sqrt{144}$$ $$h = 12 \text{ cm}$$

$$V = \frac{1}{3} \pi r^{2} h$$

Substitute $r = 5$ cm and $h = 12$ cm:

$$V = \frac{1}{3} \pi (5)^{2} (12)$$ $$V = \frac{1}{3} \pi (25) (12)$$ $$V = \frac{1}{3} \pi (300)$$ $$V = 100 \pi \text{ cm}^{3}$$

100\pi cm^{3}