Step 1: The general solution for sinϕ=21 is
ϕ=30∘+360∘norϕ=150∘+360∘n,
where n is any integer.
Step 2: Substitute ϕ=25θ.
25θ=30∘+360∘nor25θ=150∘+360∘n.
Step 3: Solve for θ.
First equation:
θ=52(30∘+360∘n)=12∘+144∘n.
Second equation:
θ=52(150∘+360∘n)=60∘+144∘n.
Step 4: Apply 0∘<θ<180∘.
For θ=12∘+144∘n:
- n=0: θ=12∘
- n=1: θ=156∘
- n=2: θ=300∘>180∘
- n=−1: θ=−132∘<0∘
For θ=60∘+144∘n:
- n=0: θ=60∘
- n=1: θ=204∘>180∘
- n=−1: θ=−84∘<0∘
Solutions: θ=12∘,60∘,156∘
12∘,60∘,156∘