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Find the equation of a line that passes through (6,6) and which is perpendicular to another line whose equation is 9x − 3y − 6 = 0.

Mathematics

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Question 1:
Find the equation of a line that passes through (6,6)(6,6) and which is perpendicular to another line whose equation is 9x−3y−6=09x - 3y - 6 = 0.

  1. Find the gradient of the given line 9x−3y−6=09x - 3y - 6 = 0.

    Rearrange the equation into the slope-intercept form y=mx+cy = mx + c:

    3y=9x−63y = 9x - 6 y=9x3−63y = \frac{9x}{3} - \frac{6}{3} y=3x−2y = 3x - 2

    The gradient of this line is m1=3m_1 = 3.

  2. Step 2

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