We read your photo as:

Find the equation of the straight line passing for points (2, -1) and (1, 1). (ii) Simplify (d)/(d x)(x2+2 x)

Mathematics

ScanSolve AI Answer

Answers

2 parts
a

y=6x−5\mathbf{y = 6x - 5}

b

A2−16\mathbf{\frac{A}{2} - \frac{1}{6}}

Step-by-step solution

5 steps

Part a· 3 steps

Find the equation of the straight line joining the points $(2, 7)$ and $(1, 1)$.

  1. Calculate the slope (mm) of the line using the formula m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}.

    Given points (x1,y1)=(2,7)(x_1, y_1) = (2, 7) and (x2,y2)=(1,1)(x_2, y_2) = (1, 1).

    m=1−71−2m = \frac{1 - 7}{1 - 2} m=−6−1m = \frac{-6}{-1} m=6m = 6
  2. Use the point-slope form of the equation of a line, y−y1=m(x−x1)y - y_1 = m(x - x_1), with one of the points, for example (1,1)(1, 1), and the calculated slope m=6m=6.

    y−1=6(x−1)y - 1 = 6(x - 1)
  3. Simplify the equation to the slope-intercept form y=mx+cy = mx + c.

    y−1=6x−6y - 1 = 6x - 6 y=6x−6+1y = 6x - 6 + 1 y=6x−5y = 6x - 5

    The equation of the straight line is y=6x−5\boxed{\mathbf{y = 6x - 5}}.

Part b

A2−16\mathbf{\frac{A}{2} - \frac{1}{6}}

Simplify 12(A−13)\frac{1}{2}(A - \frac{1}{3}).

  1. Distribute 12\frac{1}{2} to each term inside the parenthesis.

    12(A−13)=12⋅A−12⋅13\frac{1}{2} \left(A - \frac{1}{3}\right) = \frac{1}{2} \cdot A - \frac{1}{2} \cdot \frac{1}{3}
  2. Perform the multiplication.

    =A2−16= \frac{A}{2} - \frac{1}{6}

    The simplified expression is A2−16\boxed{\mathbf{\frac{A}{2} - \frac{1}{6}}}.

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp