We read your photo as:

Find the equation of the straight line passing through the origin and perpendicular to the line segment PQ, where P is (0, 4) and Q is (-4, 0).

Mathematics

ScanSolve AI Answer

Answer

y=−x\mathbf{y = -x}

Step-by-step solution

4 steps

Okay, Chimuka, let's tackle this geometry problem.

  1. Identify the coordinates of points P and Q.

    P is (0,4)(0, 4).
    Q is (−4,0)(-4, 0).

  2. Calculate the slope of line PQ.

    The slope mm of a line passing through two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}.
    Using P(0,4)(0, 4) and Q(−4,0)(-4, 0):

    mPQ=0−4−4−0=−4−4=1m_{PQ} = \frac{0 - 4}{-4 - 0} = \frac{-4}{-4} = 1
  3. Determine the slope of the line perpendicular to PQ.

    If two lines are perpendicular, the product of their slopes is −1-1. Let the slope of the required line be mperpm_{perp}.

    mperp⋅mPQ=−1m_{perp} \cdot m_{PQ} = -1 mperp⋅1=−1m_{perp} \cdot 1 = -1 mperp=−1m_{perp} = -1
  4. Find the equation of the straight line.

    The required line passes through the origin O(0,0)(0, 0) and has a slope mperp=−1m_{perp} = -1.
    Using the point-slope form y−y1=m(x−x1)y - y_1 = m(x - x_1):

    y−0=−1(x−0)y - 0 = -1(x - 0) y=−xy = -x
Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp