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Calculate the gradient of the line segment QP, given the coordinates of Q as (0, -2) and P as (1, 1).

Mathematics

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Answer

3\text{3}

Step-by-step solution

3 steps
  1. Identify the coordinates of points Q and P.

    The coordinates are given as Q(0;−2)Q(0; -2) and P(1;1)P(1; 1).

  2. Use the gradient formula.

    The formula for the gradient mm between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is:

    m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}

    Let (x1,y1)=Q(0,−2)(x_1, y_1) = Q(0, -2) and (x2,y2)=P(1,1)(x_2, y_2) = P(1, 1).

  3. Substitute the coordinates into the formula and calculate.

    mQP=1−(−2)1−0m_{QP} = \frac{1 - (-2)}{1 - 0} mQP=1+21m_{QP} = \frac{1 + 2}{1} mQP=31m_{QP} = \frac{3}{1} mQP=3m_{QP} = 3

    The gradient of QP is 3\text{3}.

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