What is the current organizational structure of that business? Attach the organogram if available.

Formula:

$$R_p = \left( \frac{1}{R_1} + \frac{1}{R_2} \right)^{-1}$$

Substitute $R_1 = 3\,\Omega$, $R_2 = 6\,\Omega$:

$$R_p = \left( \frac{1}{3\,\Omega^{-1}} + \frac{1}{6\,\Omega^{-1}} \right)^{-1} = \left( \frac{2}{6\,\Omega^{-1}} + \frac{1}{6\,\Omega^{-1}} \right)^{-1} = \left( \frac{3}{6\,\Omega^{-1}} \right)^{-1} = 2\,\Omega$$

The 2 Ω resistor is in series with the parallel combination.

$$R_\text{total} = 2\,\Omega + R_p = 2\,\Omega + 2\,\Omega = 4\,\Omega$$

Voltage across the structure $V = 12\,\mathrm{V}$.
Formula: $I_\text{total} = \frac{V}{R_\text{total}}$

$$I_\text{total} = \frac{12\,\mathrm{V}}{4\,\Omega} = 3\,\mathrm{A}$$

The 2 Ω resistor carries the total current (series position).

$$I_{2\Omega} = I_\text{total} = 3\,\mathrm{A}$$

Final answer: 3 A
3 A