What is the current organizational structure of that business? Attach the organogram if available.

Step 1: Calculate the equivalent resistance of the parallel combination (3 Ω and 6 Ω).

Formula:
$R_p = \left( \frac{1}{R_1} + \frac{1}{R_2} \right)^{-1}$

Substitute $R_1 = 3\,\Omega$, $R_2 = 6\,\Omega$:
$R_p = \left( \frac{1}{3\,\Omega^{-1}} + \frac{1}{6\,\Omega^{-1}} \right)^{-1} = \left( \frac{2}{6\,\Omega^{-1}} + \frac{1}{6\,\Omega^{-1}} \right)^{-1} = \left( \frac{3}{6\,\Omega^{-1}} \right)^{-1} = 2\,\Omega$

Step 2: Calculate the total equivalent resistance of the structure.
The 2 Ω resistor is in series with the parallel combination.
$R_total = 2\,\Omega + R_p = 2\,\Omega + 2\,\Omega = 4\,\Omega$

Step 3: Calculate the total current in the circuit.
Voltage across the structure $V = 12\,\mathrm{V}$.
Formula: $I_total = \frac{V}{R_total}$
$I_total = \frac{12\,V}{4\,\Omega} = 3\,A$

Step 4: The current in the 2 Ω resistor.
The 2 Ω resistor carries the total current (series position).
$I_{2\Omega} = I_total = 3\,A$

Final answer: 3 A
3 \mathrm{A}