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Express the price of a packet of milk and the number of packets sold in terms of n, given an initial price of 50 shillings and an increase of 4 shillings per n, and an initial sale of 530 packets with

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Answers

2 parts
a(i)

(50+4n) shillings(50 + 4n) \text{ shillings}

a(ii)

(530−20n) packets(530 - 20n) \text{ packets}

Step-by-step solution

4 steps

Here are the expressions in terms of nn:

Part a(i)· 2 steps

The price of a packet of milk after the price was increased

  1. Identify the initial price and the increase per increment.

    The initial price is 50 shillings. The price increases by 4 shillings for each time nn.

  2. Formulate the expression for the new price.

    The new price is the initial price plus the total increase.

    New Price=50+4n\text{New Price} = 50 + 4n

    The price of a packet of milk after the price was increased is (50+4n) shillings\boxed{(50 + 4n) \text{ shillings}}.

Part a(ii)

(530−20n) packets(530 - 20n) \text{ packets}

The number of packets of milk sold after the price was increased

  1. Identify the initial number of packets sold and the decrease per increment.

    The initial number of packets sold is 530. The number of packets sold decreases by 20 for each time nn.

  2. Formulate the expression for the new number of packets sold.

    The new number of packets sold is the initial number minus the total decrease.

    New Number of Packets=530−20n\text{New Number of Packets} = 530 - 20n

    The number of packets of milk sold after the price was increased is (530−20n) packets\boxed{(530 - 20n) \text{ packets}}.

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