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Factorise the following quadratic expressions: a) 8x2 + 6x + 1 b) 3x2 - 8x + 5 c) 6x2 + 11x - 10

Mathematics

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5 parts
a

(2x + 1)(4x + 1)

b

(x - 1)(3x - 5)

c

(3x - 2)(2x + 5)

d

(x + 3)(3x - 2)

e

(2x + 3)(x + 1)

You've done a great job with these factorisation problems! Let's go through them.

a) Factorise 8x2+6x+18x^2 + 6x + 1

Your work:
Sum (SS) = 6
Product (PP) = 8×1=88 \times 1 = 8
The two numbers that multiply to 8 and add to 6 are 4 and 2.

8x2+4x+2x+18x^2 + 4x + 2x + 1 (8x2+4x)+(2x+1)(8x^2 + 4x) + (2x + 1) 4x(2x+1)+1(2x+1)4x(2x + 1) + 1(2x + 1) (2x+1)(4x+1)(2x + 1)(4x + 1)

✅ Correct.
The factorised expression is (2x+1)(4x+1)\boxed{(2x + 1)(4x + 1)}.

b) Factorise 3x2−8x+53x^2 - 8x + 5

Your work:
Sum (SS) = -8
Product (PP) = 3×5=153 \times 5 = 15
The two numbers that multiply to 15 and add to -8 are -3 and -5.

3x2−3x−5x+53x^2 - 3x - 5x + 5 (3x2−3x)+(−5x+5)(3x^2 - 3x) + (-5x + 5) 3x(x−1)−5(x−1)3x(x - 1) - 5(x - 1) (x−1)(3x−5)(x - 1)(3x - 5)

✅ Correct. Your final answer is correct. Just a minor note on the grouping step you wrote: (3x2−3x)−(5x+5)(3x^2 - 3x) - (5x + 5) would expand to 3x2−3x−5x−53x^2 - 3x - 5x - 5, which is not the original expression. It should be (3x2−3x)+(−5x+5)(3x^2 - 3x) + (-5x + 5) or 3x2−3x−5x+53x^2 - 3x - 5x + 5 directly. However, you correctly factored 3x(x−1)−5(x−1)3x(x-1) - 5(x-1), so the final result is correct.
The factorised expression is (x−1)(3x−5)\boxed{(x - 1)(3x - 5)}.

c) Factorise 6x2+11x−106x^2 + 11x - 10

Your work:
Sum (SS) = 11
Product (PP) = 6×(−10)=−606 \times (-10) = -60
The two numbers that multiply to -60 and add to 11 are 15 and -4.

6x2+15x−4x−106x^2 + 15x - 4x - 10 (6x2−4x)+(15x−10)(6x^2 - 4x) + (15x - 10) 2x(3x−2)+5(3x−2)2x(3x - 2) + 5(3x - 2) (3x−2)(2x+5)(3x - 2)(2x + 5)

✅ Correct.
The factorised expression is (3x−2)(2x+5)\boxed{(3x - 2)(2x + 5)}.

d) Factorise 3x2+7x−63x^2 + 7x - 6

Your work:
Sum (SS) = 7
Product (PP) = 3×(−6)=−183 \times (-6) = -18
The two numbers that multiply to -18 and add to 7 are 9 and -2.

3x2+9x−2x−63x^2 + 9x - 2x - 6 (3x2−2x)+(9x−6)(3x^2 - 2x) + (9x - 6) x(3x−2)+3(3x−2)x(3x - 2) + 3(3x - 2) (x+3)(3x−2)(x + 3)(3x - 2)

✅ Correct.
The factorised expression is (x+3)(3x−2)\boxed{(x + 3)(3x - 2)}.

e) Factorise 2x2+5x+32x^2 + 5x + 3

Your work:
Sum (SS) = 5
Product (PP) = 2×3=62 \times 3 = 6
The two numbers that multiply to 6 and add to 5 are 2 and 3.

2x2+2x+3x+32x^2 + 2x + 3x + 3 (2x2+2x)+(3x+3)(2x^2 + 2x) + (3x + 3) 2x(x+1)+3(x+1)2x(x + 1) + 3(x + 1) (2x+3)(x+1)(2x + 3)(x + 1)

✅ Correct.
The factorised expression is (2x+3)(x+1)\boxed{(2x + 3)(x + 1)}.

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