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Factorise the following quadratic expressions: a) K2 - 11K + 24 b) x2 + 11x + 28

Mathematics

ScanSolve AI Answer

Step-by-step solution

2 steps
  1. Factorise question 10 a).

    The expression is K2−8k−3k+24K^2 - 8k - 3k + 24.
    Group the terms:

    (K2−8k)−(3k−24)(K^2 - 8k) - (3k - 24)

    Factor out the common factor from each group:

    K(K−8)−3(K−8)K(K - 8) - 3(K - 8)

    Factor out the common binomial (K−8)(K-8):

    (K−8)(K−3)(K - 8)(K - 3)

    The factored expression is (K−8)(K−3)\boxed{(K-8)(K-3)}.

  2. Factorise question 10 b).

    The expression is x2+11x+28x^2 + 11x + 28.
    We need to find two numbers that multiply to 28 and add up to 11. These numbers are 4 and 7.
    Rewrite the middle term using these numbers:

    x2+4x+7x+28x^2 + 4x + 7x + 28

    Group the terms:

    (x2+4x)+(7x+28)(x^2 + 4x) + (7x + 28)

    Factor out the common factor from each group:

    x(x+4)+7(x+4)x(x + 4) + 7(x + 4)

    Factor out the common binomial (x+4)(x+4):

    (x+4)(x+7)(x + 4)(x + 7)

    The factored expression is $\boxed

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