This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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Q11 Step 1: First law of thermodynamics: U = q + w. For isothermal process of ideal gas, U = 0 (since U depends only on T). Thus, q = -w. U = 0 Q12 Step 1: Work for reversible isothermal expansion of ideal gas: w = -nRT ((V_2)/(V_1)) Step 2: Substitute n = 1 mol, R = 8.314 J/mol·K, T = 300 K, V_1 = 10 L, V_2 = 100 L. nRT = (1)(8.314)(300) = 2494.2 J Step 3: (100/10) = 10 = 2.3026 Step 4: Simplify: w = -2494.2 × 2.3026 = -5746 J = -5.75 kJ ≈ -5.7 kJ -5.7 kJ Q13 Step 1: Moles of ethane: assume mass = 60 g, M = 30 g/mol, so $n =