200 g of calcium carbonate completely reacted with dilute HCL in 2 minute.What is the rate of reaction in mol min^-1

Chemistry

ScanSolve AI Answer

4 steps

Answer

48.00 g/mol

The rate of reaction is 1 mol min⁻¹.

Here's how to calculate it:

  1. Calculate the molar mass of calcium carbonate (CaCO₃):

    • Ca: 40.08 g/mol
    • C: 12.01 g/mol
    • O: 3 * 16.00 g/mol = 48.00 g/mol
    • Molar mass of CaCO₃ = 40.08 + 12.01 + 48.00 = 100.09 g/mol

  2. Calculate the number of moles of calcium carbonate:

    • Moles = Mass / Molar mass
    • Moles of CaCO₃ = 200 g / 100.09 g/mol = 1.9982 mol

  3. Calculate the rate of reaction:

    • Rate = Moles of reactant consumed / Time
    • Rate = 1.9982 mol / 2 min = 0.9991 mol min⁻¹

  4. Apply significant figures:

    • The mass (200 g) has three significant figures.
    • The time (2 minute) has one significant figure.
    • The final answer should be rounded to the least number of significant figures, which is one.
    • 0.9991 mol min⁻¹ rounded to one significant figure is 1 mol min⁻¹.
Was this helpful?

Need help with your own homework?

Get instant step-by-step solutions to any question. Free to start.

Ask Your Question
Got a syllabus? Photograph it and I'll tell you what's due and what's worth the most.

More Chemistry Questions

QWhat's an isotopeQWhat is an isotopeQASSIGNMENT Write all the possible isomers of Butanol and make sure you define each of the isomerism…QWhat us the formula for butanolQThe diagram shows some reactions of butanoic acid. A, B, C and D are different substances. Identify…
See all Chemistry questions →

Still have questions?

Quick Answer

The rate of reaction is 1 mol min⁻¹. Here's how to calculate it: 1.

200 g of calcium carbonate completely reacted with dilute HCL in 2 minute.What is the rate of reaction in mol min^-1
Chemistry

This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

ScanSolve AI Answer
The rate of reaction is 1 mol min⁻¹. Here's how to calculate it: 1. Calculate the molar mass of calcium carbonate (CaCO₃): Ca: 40.08 g/mol C: 12.01 g/mol O: 3 16.00 g/mol = 48.00 g/mol Molar mass of CaCO₃ = 40.08 + 12.01 + 48.00 = 100.09 g/mol 2. Calculate the number of moles of calcium carbonate: Moles = Mass / Molar mass Moles of CaCO₃ = 200 g / 100.09 g/mol = 1.9982 mol 3. Calculate the rate of reaction: Rate = Moles of reactant consumed / Time Rate = 1.9982 mol / 2 min = 0.9991 mol min⁻¹ 4. Apply significant figures: The mass (200 g) has three significant figures. The time (2 minute) has one significant figure. The final answer should be rounded to the least number of significant figures, which is one. 0.9991 mol min⁻¹ rounded to one significant figure is 1 mol min⁻¹.