200 g of calcium carbonate completely reacted with dilute HCL in 2 minute.What is the rate of reaction in mol min⁻¹
Chemistry
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Answer
The rate of reaction is 1 mol min⁻¹.
Step-by-step solution
4 stepsHere's how to calculate it:
Calculate the molar mass of calcium carbonate (CaCO₃)
- Ca: 40.08 g/mol
- C: 12.01 g/mol
- O: 3 * 16.00 g/mol = 48.00 g/mol
- Molar mass of CaCO₃ = 40.08 + 12.01 + 48.00 = 100.09 g/mol
Calculate the number of moles of calcium carbonate
- Moles = Mass / Molar mass
- Moles of CaCO₃ = 200 g / 100.09 g/mol = 1.9982 mol
Calculate the rate of reaction
- Rate = Moles of reactant consumed / Time
- Rate = 1.9982 mol / 2 min = 0.9991 mol min⁻¹
Apply significant figures
- The mass (200 g) has three significant figures.
- The time (2 minute) has one significant figure.
- The final answer should be rounded to the least number of significant figures, which is one.
- 0.9991 mol min⁻¹ rounded to one significant figure is 1 mol min⁻¹.
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