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Solve the following algebraic problems: 1. Make h the subject of V = pi r2 h. 2. Expand (2x-3)(x-5). 3. Factor 9a - 27. 4. Solve 4/(x+10) = 3/(x+5).

Mathematics

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Step-by-step solution

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29)

  1. Start with the given formula.

    V=πr2hV = \pi r^2 h
  2. To make hh the subject, divide both sides of the equation by πr2\pi r^2.

    Vπr2=πr2hπr2\frac{V}{\pi r^2} = \frac{\pi r^2 h}{\pi r^2}
  3. Simplify the equation.

    h=Vπr2h = \frac{V}{\pi r^2}

    The correct option is C. h=Vπr2\boxed{\text{C. } h = \frac{V}{\pi r^2}}.

    30)

  4. Expand the expression (2x−3)(x−5)(2x - 3)(x - 5) using the distributive property (FOIL method).

    (2x−3)(x−5)=2x(x)+2x(−5)−3(x)−3(−5)(2x - 3)(x - 5) = 2x(x) + 2x(-5) - 3(x) - 3(-5)
  5. Perform the multiplications.

    =2x2−10x−3x+15= 2x^2 - 10x - 3x + 15
  6. Combine the like terms (the xx terms).

    =2x2−(10x+3x)+15= 2x^2 - (10x + 3x) + 15 =2x2−13x+15= 2x^2 - 13x + 15

    The correct option is D. 2x2−13x+15\boxed{\text{D. } 2x^2 - 13x + 15}.

    31)

  7. Identify the common factor in the terms $9a$ and 27.

    The greatest common factor of 9 and 27 is 9.

  8. Factor out the common factor.

    9a−27=9(a)−9(3)9a - 27 = 9(a) - 9(3) =9(a−3)= 9(a - 3)

    The correct option is A. 9(a−3)\boxed{\text{A. } 9(a - 3)}.

    Word (after 31)

  9. Let the certain number be xx.

    Translate the first part of the statement: "When 4 is divided by the sum of a certain number and 10"

    4x+10\frac{4}{x + 10}

    Translate the second part of the statement: "the result is the same as dividing 3 by the sum of that number and 5"

    3x+5\frac{3}{x + 5}
  10. Set up the equation.

    4x+10=3x+5\frac{4}{x + 10} = \frac{3}{x + 5}
  11. Cross-multiply to solve for xx.

    4(x+5)=3(x+10)4(x + 5) = 3(x + 10)
  12. Distribute the numbers on both sides.

    4x+20=3x+304x + 20 = 3x + 30
  13. Subtract $3x$ from both sides.

    4x−3x+20=304x - 3x + 20 = 30 x+20=30x + 20 = 30
  14. Subtract 20 from both sides.

    x=30−20x = 30 - 20 x=10x = 10

    The number is E. 10\boxed{\text{E. } 10} (assuming E is 10, as A, B, C, D are 5, 7, 9, 11).

    Word (after the previous word problem)

  15. Let the father's age be FF and the son's age be SS.

    The difference between their ages is 28:

    F−S=28F - S = 28
  16. Substitute the given father's age, F=42F = 42.

    42−S=2842 - S = 28
  17. Solve for SS.

    Subtract 42 from both sides:

    −S=28−42-S = 28 - 42 −S=−14-S = -14

    Multiply by -1:

    S=14S = 14

    The son's age is 14 years\boxed{14 \text{ years}}.

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