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Here are the solutions to the math problems: a) Expand: (2x+3)(4-3x) b) Factorize completely: x2 - 7x + 10 c) Solve the quadratic equation: x2 − 5x − 6 = 0

Mathematics

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Answers

2 parts
b

(x-2)(x-5)

c

x=−1 or x=6x = -1 \text{ or } x = 6

Step-by-step solution

9 steps

here are the solutions to the math problems:

21. a) Expand: (2x+3)(4−3x)(2x+3)(4-3x)

Step 1: Use the distributive property (FOIL method).

(2x+3)(4−3x)=2x(4)+2x(−3x)+3(4)+3(−3x)(2x+3)(4-3x) = 2x(4) + 2x(-3x) + 3(4) + 3(-3x)

Step 2: Multiply the terms.

=8x−6x2+12−9x= 8x - 6x^2 + 12 - 9x

Step 3: Combine like terms.

=−6x2+(8x−9x)+12= -6x^2 + (8x - 9x) + 12 =−6x2−x+12= -6x^2 - x + 12

The expanded expression is −6x2−x+12\boxed{-6x^2 - x + 12}.

Part b· 4 steps

Factorize completely:** x2−7x+10x^2 - 7x + 10

  1. Find two numbers that multiply to 10 and add up to −7-7.

    The numbers are −2-2 and −5-5.

  2. Rewrite the middle term using these numbers.

    x2−2x−5x+10x^2 - 2x - 5x + 10
  3. Factor by grouping.

    x(x−2)−5(x−2)x(x-2) - 5(x-2)
  4. Factor out the common binomial.

    (x−2)(x−5)(x-2)(x-5)

    The completely factorized expression is (x−2)(x−5)\boxed{(x-2)(x-5)}.

Part c

x=−1 or x=6x = -1 \text{ or } x = 6

Solve the quadratic equation:** x2−5x−6=0x^2 - 5x - 6 = 0

  1. Find two numbers that multiply to −6-6 and add up to −5-5.

    The numbers are −6-6 and 1.

  2. Rewrite the middle term using these numbers.

    x2−6x+x−6=0x^2 - 6x + x - 6 = 0
  3. Factor by grouping.

    x(x−6)+1(x−6)=0x(x-6) + 1(x-6) = 0
  4. Factor out the common binomial.

    (x+1)(x−6)=0(x+1)(x-6) = 0
  5. Set each factor equal to zero and solve for xx.

    x+1=0orx−6=0x+1 = 0 \quad \text{or} \quad x-6 = 0 x=−1orx=6x = -1 \quad \text{or} \quad x = 6

    The solutions to the quadratic equation are x=−1 or x=6\boxed{x = -1 \text{ or } x = 6}.

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