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Here are the solutions to the mathematics problems: SUBJECT: MATHEMATICS a) Simplify (7x - 4) - (4x - 12) b) Solve the equation (x)/(3) + (x)/(2) = (5)/(2) a) Simplify ((x-3)(x+1))/(x)

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Here are the solutions to the mathematics problems:

SUBJECT: MATHEMATICS

  1. a) Simplify (7x−4)−(4x−12)(7x - 4) - (4x - 12)
  1. Distribute the negative sign to the terms in the second parenthesis.

    $$
    (7x - 4) - (4x - 12) = 7x - 4 - 4x + 12
    $$
    
  2. Group like terms.

    $$
    (7x - 4x) + (-4 + 12)
    $$
    
  3. Combine like terms.

    $$
    3x + 8
    $$
    The simplified expression is:
    $$
    \boxed{3x + 8}
    $$
    
    **b)** Solve the equation $\frac{x}{3} + \frac{x}{2} = \frac{5}{2}$
    
  4. Find the least common multiple (LCM) of the denominators (3, 2, 2), which is 6.

  5. Multiply every term in the equation by the LCM to eliminate the denominators.

    $$
    6 \left(\frac{x}{3}\right) + 6 \left(\frac{x}{2}\right) = 6 \left(\frac{5}{2}\right)
    $$
    
  6. Simplify the terms.

    $$
    2x + 3x = 15
    $$
    
  7. Combine like terms on the left side.

    $$
    5x = 15
    $$
    
  8. Divide by 5 to solve for xx.

    $$
    x = \frac{15}{5}
    $$
    $$
    x = 3
    $$
    The solution for $x$ is:
    $$
    \boxed{x = 3}
    $$
    

    2. a) Simplify (x−3)(x+1)x\frac{(x-3)(x+1)}{x}

  9. Expand the numerator using the FOIL method (First, Outer, Inner, Last).

    $$
    (x-3)(x+1) = x(x) + x(1) - 3(x) - 3(1)
    $$
    $$
    = x^2 + x - 3x - 3
    $$
    $$
    = x^2 - 2x - 3
    $$
    
  10. Write the expression with the expanded numerator.

    $$
    \frac{x^2 - 2x - 3}{x}
    $$
    
  11. Divide each term in the numerator by xx.

    $$
    \frac{x^2}{x} - \frac{2x}{x} - \frac{3}{x}
    $$
    $$
    x - 2 - \frac{3}{x}
    $$
    The simplified expression is:
    $$
    \boxed{x - 2 - \frac{3}{x}}
    $$
    
    **b)** Simplify $8x^2 \times \frac{3xy}{6xy^2}$
    
  12. Multiply the terms.

    $$
    \frac{8x^2 \cdot 3xy}{6xy^2}
    $$
    
  13. Multiply the coefficients and combine the variables in the numerator.

    $$
    \frac{24x^3y}{6xy^2}
    $$
    
  14. Simplify the coefficients and variables.

    Divide 24 by 6, x3x^3 by xx, and yy by y2y^2. 246⋅x3x⋅yy2 \frac{24}{6} \cdot \frac{x^3}{x} \cdot \frac{y}{y^2} 4⋅x(3−1)⋅y(1−2) 4 \cdot x^{(3-1)} \cdot y^{(1-2)} 4x2y−1 4x^2y^{-1} 4x2y \frac{4x^2}{y} The simplified expression is: 4x2y \boxed{\frac{4x^2}{y}}

    1. a) Expand (x+1)(x−2)(x+1)(x-2)
  15. Use the FOIL method (First, Outer, Inner, Last).

    $$
    (x+1)(x-2) = x(x) + x(-2) + 1(x) + 1(-2)
    $$
    $$
    = x^2 - 2x + x - 2
    $$
    
  16. Combine like terms.

    $$
    = x^2 - x - 2
    $$
    The expanded expression is:
    $$
    \boxed{x^2 - x - 2}
    $$
    
    **b)** Find the HCF of $4x^2y$ and $6xyz$
    
  17. Find the prime factorization of each term.

    $$
    4x^2y = 2^2 \cdot x^2 \cdot y
    $$
    $$
    6xyz = 2 \cdot 3 \cdot x \cdot y \cdot z
    $$
    
  18. Identify the common factors and their lowest powers.

    • Common numerical factor: 212^1 (from 222^2 and 212^1)
    • Common variable xx: x1x^1 (from x2x^2 and x1x^1)
    • Common variable yy: y1y^1 (from y1y^1 and y1y^1)
    • Variable zz is not common.
  19. Multiply the common factors.

    $$
    \text{HCF} = 2 \cdot x \cdot y
    $$
    $$
    \text{HCF} = 2xy
    $$
    The HCF is:
    $$
    \boxed{2xy}
    $$
    

    4. a) Which of the following inequalities is sketched in the figure below? The figure shows a number line with a closed circle at -1 and the line shaded to the right of -1. - A closed circle indicates that the number -1 is included in the solution set. This means "greater than or equal to" (≥\ge) or "less than or equal to" (≤\le). - Shading to the right indicates values greater than -1. Combining these, the inequality represents all numbers xx that are greater than or equal to -1. x≥−1 x \ge -1 The inequality is: x≥−1 \boxed{x \ge -1}

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