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Here are the solutions to the mathematics questions: 1. Simplify 272/3. 2. Express 7/19 as a percentage: correct to 1 decimal place. 3. The angle in a semicircle is . 4. Simplify rac10sqrt(32)

Mathematics

ScanSolve AI Answer

Answer

D

9

Step-by-step solution

39 steps

Here are the solutions to the mathematics questions:

1. Simplify 272/327^{2/3}

  1. Rewrite the expression using roots and powers.

    272/3=(273)227^{2/3} = (\sqrt[3]{27})^2
  2. Calculate the cube root of 27.

    273=3\sqrt[3]{27} = 3
  3. Square the result.

    32=93^2 = 9

    The correct answer is (d) 9.

    9\boxed{9}

    2. Express 7/197/19 as a percentage: correct to 1 decimal place

  4. Convert the fraction to a decimal.

    719≈0.368421\frac{7}{19} \approx 0.368421
  5. Multiply by 100 to express as a percentage.

    0.368421×100%=36.8421%0.368421 \times 100\% = 36.8421\%
  6. Round to one decimal place.

    36.8%36.8\%

    The correct answer is (d) 36.8%.

    36.8%\boxed{36.8\%}

    3. The angle in a semicircle is ____
    The angle subtended by a diameter at any point on the circumference of a circle is a right angle.
    The correct answer is (c) 90∘90^\circ.

    90∘\boxed{90^\circ}

    4. Simplify 1032\frac{10}{\sqrt{32}}

  7. Simplify the square root in the denominator.

    32=16×2=16×2=42\sqrt{32} = \sqrt{16 \times 2} = \sqrt{16} \times \sqrt{2} = 4\sqrt{2}
  8. Substitute the simplified square root back into the expression.

    1042\frac{10}{4\sqrt{2}}
  9. Rationalize the denominator by multiplying the numerator and denominator by 2\sqrt{2}.

    1042×22=1024×2=1028\frac{10}{4\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}} = \frac{10\sqrt{2}}{4 \times 2} = \frac{10\sqrt{2}}{8}
  10. Simplify the fraction.

    1028=524\frac{10\sqrt{2}}{8} = \frac{5\sqrt{2}}{4}

    The correct answer is (a) 524\frac{5\sqrt{2}}{4}.

    524\boxed{\frac{5\sqrt{2}}{4}}

    5. If y=7y=7, then dy/dx=dy/dx=

  11. The function is y=7y=7.

    This is a constant function.

  12. The derivative of any constant with respect to xx is 0.

    dydx=ddx(7)=0\frac{dy}{dx} = \frac{d}{dx}(7) = 0

    The correct answer is (c) 0.

    0\boxed{0}

    6. The derivative of xnx^n is ____
    Using the power rule for differentiation, if y=xny = x^n, then dydx=nxn−1\frac{dy}{dx} = nx^{n-1}.
    The correct answer is (c) nxn−1nx^{n-1}.

    nxn−1\boxed{nx^{n-1}}

    7. Convert 1810 to base 3

  13. Divide 1810 by 3 and record the remainder.

    1810÷3=603 remainder 11810 \div 3 = 603 \text{ remainder } 1
  14. Continue dividing the quotient by 3.

    603÷3=201 remainder 0603 \div 3 = 201 \text{ remainder } 0 201÷3=67 remainder 0201 \div 3 = 67 \text{ remainder } 0 67÷3=22 remainder 167 \div 3 = 22 \text{ remainder } 1 22÷3=7 remainder 122 \div 3 = 7 \text{ remainder } 1 7÷3=2 remainder 17 \div 3 = 2 \text{ remainder } 1 2÷3=0 remainder 22 \div 3 = 0 \text{ remainder } 2
  15. Read the remainders from bottom to top.

    181010=211100131810_{10} = 2111001_3

    The options provided are 200, 201, 210, 220. None of these match the calculated answer. There might be a typo in the question or options. Assuming the question meant to ask for a smaller number or the options are incorrect. If we were to pick the closest looking option, it's not clear. However, based on the calculation, the answer is 211100132111001_3.
    Let's re-check the options. It's possible the question meant to convert a different number or the options are for a different base. Given the options are small, it's highly likely the question is flawed or refers to a different problem. I will provide the correct conversion for 1810 to base 3.

    21110013\boxed{2111001_3}

    8. The nth term of an A.P is ____
    The formula for the nth term of an Arithmetic Progression (A.P.) is an=a+(n−1)da_n = a + (n-1)d, where aa is the first term and dd is the common difference.
    The correct answer is (b) a+(n−1)da + (n-1)d.

    a+(n−1)d\boxed{a + (n-1)d}

    9. If 2x5=142x^5 = 14, Find xx

  16. Divide both sides by 2.

    x5=142x^5 = \frac{14}{2} x5=7x^5 = 7
  17. Take the fifth root of both sides.

    x=75x = \sqrt[5]{7}

    The options are 1, 2, 3, 4. None of these are 75\sqrt[5]{7}. There might be a typo in the question. If the question was 2x=142x = 14, then x=7x=7. If it was x2=14x^2=14, x=14x=\sqrt{14}. If it was 2x=142^x=14, x=log⁡214x=\log_2 14. Given the options, it's possible the question intended to be 2x=142x=14. If we assume 2x=142x=14, then x=7x=7. However, the question clearly states 2x5=142x^5=14.
    Based on the given equation:

    x=75\boxed{x = \sqrt[5]{7}}

    10. If sin⁡θ=3/5\sin \theta = 3/5, find cos⁡θ\cos \theta

  18. Use the Pythagorean identity sin⁡2θ+cos⁡2θ=1\sin^2 \theta + \cos^2 \theta = 1.

    (35)2+cos⁡2θ=1\left(\frac{3}{5}\right)^2 + \cos^2 \theta = 1 925+cos⁡2θ=1\frac{9}{25} + \cos^2 \theta = 1
  19. Solve for cos⁡2θ\cos^2 \theta.

    cos⁡2θ=1−925\cos^2 \theta = 1 - \frac{9}{25} cos⁡2θ=2525−925\cos^2 \theta = \frac{25}{25} - \frac{9}{25} cos⁡2θ=1625\cos^2 \theta = \frac{16}{25}
  20. Take the square root of both sides.

    cos⁡θ=±1625\cos \theta = \pm\sqrt{\frac{16}{25}} cos⁡θ=±45\cos \theta = \pm\frac{4}{5}

    Assuming θ\theta is in the first quadrant (or where cosine is positive), cos⁡θ=4/5\cos \theta = 4/5.
    The correct answer is (a) 4/54/5.

    45\boxed{\frac{4}{5}}

    11. The distance between (1,2)(1,2) and (4,6)(4,6) is ____

  21. Use the distance formula d=(x2−x1)2+(y2−y1)2d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}.

    Let (x1,y1)=(1,2)(x_1, y_1) = (1,2) and (x2,y2)=(4,6)(x_2, y_2) = (4,6).

  22. Substitute the coordinates into the formula.

    d=(4−1)2+(6−2)2d = \sqrt{(4-1)^2 + (6-2)^2} d=(3)2+(4)2d = \sqrt{(3)^2 + (4)^2} d=9+16d = \sqrt{9 + 16} d=25d = \sqrt{25} d=5d = 5

    The correct answer is (c) 5.

    5\boxed{5}

    12. Given f(x)=x2−4f(x) = x^2 - 4. Find f(3)f(3).

  23. Substitute x=3x=3 into the function f(x)f(x).

    f(3)=(3)2−4f(3) = (3)^2 - 4
  24. Calculate the value.

    f(3)=9−4f(3) = 9 - 4 f(3)=5f(3) = 5

    The correct answer is (b) 5.

    5\boxed{5}

    13. Evaluate 23×54(mod7)23 \times 54 \pmod{7}

  25. Find the remainder of 23 when divided by 7.

    23=3×7+223 = 3 \times 7 + 2

    So, 23≡2(mod7)23 \equiv 2 \pmod{7}.

  26. Find the remainder of 54 when divided by 7.

    54=7×7+554 = 7 \times 7 + 5

    So, 54≡5(mod7)54 \equiv 5 \pmod{7}.

  27. Multiply the remainders and find the remainder of the product when divided by 7.

    23×54≡2×5(mod7)23 \times 54 \equiv 2 \times 5 \pmod{7} 23×54≡10(mod7)23 \times 54 \equiv 10 \pmod{7}
  28. Find the remainder of 10 when divided by 7.

    10=1×7+310 = 1 \times 7 + 3

    So, 10≡3(mod7)10 \equiv 3 \pmod{7}.
    The correct answer is (b) 3.

    3\boxed{3}

    14. Simplify x−44−x−36−x−1812\frac{x-4}{4} - \frac{x-3}{6} - \frac{x-18}{12}

  29. Find the least common multiple (LCM) of the denominators 4, 6, and 12.

    The LCM is 12.

  30. Rewrite each fraction with the common denominator.

    x−44=3(x−4)12=3x−1212\frac{x-4}{4} = \frac{3(x-4)}{12} = \frac{3x-12}{12} x−36=2(x−3)12=2x−612\frac{x-3}{6} = \frac{2(x-3)}{12} = \frac{2x-6}{12} x−1812=x−1812\frac{x-18}{12} = \frac{x-18}{12}
  31. Combine the fractions.

    3x−1212−2x−612−x−1812\frac{3x-12}{12} - \frac{2x-6}{12} - \frac{x-18}{12} =(3x−12)−(2x−6)−(x−18)12= \frac{(3x-12) - (2x-6) - (x-18)}{12}
  32. Distribute the negative signs and combine like terms in the numerator.

    =3x−12−2x+6−x+1812= \frac{3x-12 - 2x+6 - x+18}{12} =(3x−2x−x)+(−12+6+18)12= \frac{(3x-2x-x) + (-12+6+18)}{12} =0x+1212= \frac{0x + 12}{12} =1212= \frac{12}{12} =1= 1

    The options are x−18x-18, x−6x-6, x−18x-18, x−6x-6. None of these match the answer 1. There might be a typo in the question or options.

    1\boxed{1}

    15. Three boys shared 10,500.00 in the ratio 6:7:86:7:8. Find the largest share.

  33. Find the total number of ratio parts.

    6+7+8=216 + 7 + 8 = 21
  34. Calculate the value of one ratio part.

    Value per part=10,50021=500\text{Value per part} = \frac{10,500}{21} = 500
  35. The largest share corresponds to the largest ratio part, which is 8.

    Largest share=8×500=4,000\text{Largest share} = 8 \times 500 = 4,000

    The correct answer is (a) 4,000.00.

    4,000.00\boxed{4,000.00}

    16. If 43x=16x+143x = 16^{x+1}, Find the value of xx
    This question appears to have a typo. It is highly probable that it should be 43x=16x+14^{3x} = 16^{x+1}. I will solve it with this assumption.

  36. Express both sides with the same base.

    Since 16=4216 = 4^2, we can write:

    43x=(42)x+14^{3x} = (4^2)^{x+1}
  37. Apply the exponent rule (am)n=amn(a^m)^n = a^{mn}.

    43x=42(x+1)4^{3x} = 4^{2(x+1)} 43x=42x+24^{3x} = 4^{2x+2}
  38. Equate the exponents since the bases are the same.

    3x=2x+23x = 2x+2
  39. Solve for

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