Solve the following differentiation problems using the chain rule.
|Mathematics
Solve the following differentiation problems using the chain rule.
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11 steps
Answer
15(3x+2)4
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Here are the solutions using the chain rule:
Basic Polynomial Composition:
To find dxdy for y=(3x+2)5:
dxdy=5(3x+2)5−1⋅dxd(3x+2)dxdy=5(3x+2)4⋅315(3x+2)4
To differentiate f(x)=(2x2−5x+1)4:
f′(x)=4(2x2−5x+1)4−1⋅dxd(2x2−5x+1)f′(x)=4(2x2−5x+1)3⋅(4x−5)4(4x−5)(2x2−5x+1)3
To find f′(x) if f(x)=(4−x2)3:
f′(x)=3(4−x2)3−1⋅dxd(4−x2)f′(x)=3(4−x2)2⋅(−2x)−6x(4−x2)2
Square Root and Fractional Powers:
To differentiate y=5x2+3x−1=(5x2+3x−1)1/2:
dxdy=21(5x2+3x−1)21−1⋅dxd(5x2+3x−1)dxdy=21(5x2+3x−1)−1/2⋅(10x+3)\frac{10x + 3{2\sqrt{5x^2 + 3x - 1}}}
To find dxdy if y=(x3+2x)1/3:
dxdy=31(x3+2x)31−1⋅dxd(x3+2x)dxdy=31(x3+2x)−2/3⋅(3x2+2)\frac{3x^2 + 2{3(x^3 + 2x)^{2/3}}}
To find the derivative of f(x)=(1−2x)−2:
f′(x)=−2(1−2x)−2−1⋅dxd(1−2x)f′(x)=−2(1−2x)−3⋅(−2)f′(x)=4(1−2x)−3\frac{4{(1 - 2x)^3}}
Trigonometric Functions:
To differentiate y=sin(4x2+3x):
dxdy=cos(4x2+3x)⋅dxd(4x2+3x)dxdy=cos(4x2+3x)⋅(8x+3)(8x+3)cos(4x2+3x)
To find f′(x) if f(x)=cos3(2x)=(cos(2x))3:
f′(x)=3(cos(2x))3−1⋅dxd(cos(2x))f′(x)=3cos2(2x)⋅(−sin(2x))⋅dxd(2x)f′(x)=3cos2(2x)⋅(−sin(2x))⋅2−6cos2(2x)sin(2x)
To find dxdy if y=tan(x2−5x):
dxdy=sec2(x2−5x)⋅dxd(x2−5x)dxdy=sec2(x2−5x)⋅(2x−5)(2x−5)sec2(x2−5x)
To differentiate y=sin2(3x+π/4)=(sin(3x+π/4))2:
dxdy=2sin(3x+π/4)⋅dxd(sin(3x+π/4))dxdy=2sin(3x+π/4)⋅cos(3x+π/4)⋅dxd(3x+π/4)dxdy=2sin(3x+π/4)⋅cos(3x+π/4)⋅36sin(3x+π/4)cos(3x+π/4)
Exponential Functions:
To find dxdy if y=e3x2+2x:
dxdy=e3x2+2x⋅dxd(3x2+2x)dxdy=e3x2+2x⋅(6x+2)
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