Solve the following inequality |5x – 7| > 2x + 7. A sequence Sn is such that U(x+1) = 3Un – 1 and U1 = 1. Find the first 5 terms of the sequence.

The problem states that the cylindrical surface area $A$ varies jointly as its base diameter $d$ and its height $h$. This can be written as:

$$A = kdh$$

where $k$ is the constant of proportionality.

Given the base radius $r = 0.97 \, \text{m}$, the base diameter $d$ is:

$$d = 2r = 2 \times 0.97 \, \text{m} = 1.94 \, \text{m}$$

Given $A = 3.26 \, \text{m}^2$, $d = 1.94 \, \text{m}$, and $h = 1.82 \, \text{m}$:

$$3.26 = k \times (1.94) \times (1.82)$$ $$3.26 = k \times 3.5308$$ $$k = \frac{3.26}{3.5308}$$

To express $k$ as an exact fraction, we can write:

$$k = \frac{326}{35308} = \frac{163}{17654}$$

Substitute the value of $k$ back into the joint variation equation:

$$A = \frac{163}{17654} dh$$

The relationship between $A$, $d$, and $h$ is:

$$\boxed{A = \frac{163}{17654} dh}$$