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Solve the following problems: 4. A car costs 6000. If a down payment of 15% is made, how much is still owed? 5. Factor the expression 3a2 + 3a - 18. 6. Simplify (x2-9)/(4x-12) / (x+3)/(2)$.

Mathematics

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Answer

D

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Here are the solutions to the problems.

4.

  1. Calculate the amount of the down payment.

    The down payment is 15%15\% of the car's cost. Down payment=0.15×$6000=$900\text{Down payment} = 0.15 \times \$6000 = \$900

  2. Calculate the remaining amount to pay.

    The amount still to pay is the total cost minus the down payment. Amount to pay=$6000−$900=$5100\text{Amount to pay} = \$6000 - \$900 = \$5100 The correct option is d.
    The amount he still has to pay is \boxed{\text{\5100}}$.

    5.

  3. Factor out the greatest common factor from the expression.

    The expression is 3a2+3a−183a^2 + 3a - 18. The common factor is 3.

    3a2+3a−18=3(a2+a−6)3a^2 + 3a - 18 = 3(a^2 + a - 6)
  4. Factor the quadratic expression inside the parentheses.

    We need two numbers that multiply to −6-6 and add to 1. These numbers are 3 and −2-2.

    a2+a−6=(a+3)(a−2)a^2 + a - 6 = (a+3)(a-2)
  5. Combine the factors.

    3(a2+a−6)=3(a+3)(a−2)3(a^2 + a - 6) = 3(a+3)(a-2)

    The correct option is d.
    The factored and simplified expression is 3(a+3)(a−2)\boxed{3(a+3)(a-2)}.

    6.

  6. Factor the numerator and denominator of the first fraction.

    The numerator x2−9x^2 - 9 is a difference of squares: x2−9=(x−3)(x+3)x^2 - 9 = (x-3)(x+3).
    The denominator 4x−124x - 12 has a common factor of 4: 4x−12=4(x−3)4x - 12 = 4(x-3).
    So the first fraction becomes (x−3)(x+3)4(x−3)\frac{(x-3)(x+3)}{4(x-3)}.

  7. Rewrite the division as multiplication by the reciprocal of the second fraction.

    (x−3)(x+3)4(x−3)÷x+32=(x−3)(x+3)4(x−3)×2x+3\frac{(x-3)(x+3)}{4(x-3)} \div \frac{x+3}{2} = \frac{(x-3)(x+3)}{4(x-3)} \times \frac{2}{x+3}
  8. Cancel common factors.

    Assuming x≠3x \neq 3 and x≠−3x \neq -3, we can cancel (x−3)(x-3) and (x+3)(x+3).

    (x−3)(x+3)4(x−3)×2x+3=14×2=24=12\frac{\cancel{(x-3)}\cancel{(x+3)}}{4\cancel{(x-3)}} \times \frac{2}{\cancel{x+3}} = \frac{1}{4} \times 2 = \frac{2}{4} = \frac{1}{2}

    The correct option is b.
    The simplified expression

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