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Solve the following problems involving logarithms: a) Find log(6.02214076 x 1023). b) If log x = -1.3649, find i) the characteristic and ii) the mantissa. c) Find the antilog of -1.3649.

Mathematics

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11. Logarithms

a) Use the calculator to find the logarithm of the constant 6.02214076×10236.02214076 \times 10^{23}.
Let N=6.02214076×1023N = 6.02214076 \times 10^{23}.
We need to find log⁡10N\log_{10} N.
Using the logarithm property log⁡(AB)=log⁡A+log⁡B\log(AB) = \log A + \log B:

log⁡10N=log⁡10(6.02214076)+log⁡10(1023)\log_{10} N = \log_{10}(6.02214076) + \log_{10}(10^{23}) log⁡10N=log⁡10(6.02214076)+23\log_{10} N = \log_{10}(6.02214076) + 23

Using a calculator:

log⁡10(6.02214076)≈0.779750\log_{10}(6.02214076) \approx 0.779750

So,

log⁡10N≈0.779750+23\log_{10} N \approx 0.779750 + 23 log⁡10N≈23.779750\log_{10} N \approx 23.779750

The logarithm of the constant is 23.779750\boxed{23.779750}.

b) Abdul works out the logarithm of a number as −1.3649-1.3649. Determine the:

i) Characteristics in the logarithm:
To find the characteristic, we express the logarithm in the form characteristic+mantissa\text{characteristic} + \text{mantissa}, where the mantissa is positive.

−1.3649=−1−0.3649-1.3649 = -1 - 0.3649

To make the mantissa positive, we add and subtract 1:

−1−1+1−0.3649=−2+(1−0.3649)-1 - 1 + 1 - 0.3649 = -2 + (1 - 0.3649) −2+0.6351-2 + 0.6351

The characteristic is the integer part, which is −2-2. This is often written as 2ˉ\bar{2}.
The characteristic is −2\boxed{-2}.

ii) Mantissa in the logarithm:
From the previous step, the mantissa is the positive decimal part.
The mantissa is 0.6351\boxed{0.6351}.

c) Hence use tables of antilogarithms to determine the value of 10−1.364910^{-1.3649}.
We need to find the antilogarithm of −1.3649-1.3649.
From part (b), we know that −1.3649=2ˉ.6351-1.3649 = \bar{2}.6351.
To find the antilog of 2ˉ.6351\bar{2}.6351:

  1. Look up the mantissa 0.6351 in the antilogarithm tables.
    • Antilog of 0.635 is 4.315.
    • The mean difference for 1 (in the row for 63) is 1.
    • So, the antilog of 0.6351 is 4.315+0.001=4.3164.315 + 0.001 = 4.316.
  2. The characteristic is 2ˉ\bar{2}, which means the decimal point should be placed such that there is one zero immediately after the decimal point before the first significant digit. (Alternatively, 102ˉ.6351=10−2×100.6351=0.01×4.31610^{\bar{2}.6351} = 10^{-2} \times 10^{0.6351} = 0.01 \times 4.316). Therefore, the value is 0.04316. The value of 10−1.364910^{-1.3649} is 0.04316\boxed{0.04316}.

12. A grocery store has fruits in racks as shown in the table.
Taking xx to represent banana and yy to represent orange, work out a simplified expression for the total number of fruits in the store.

From the table:
Number of bananas in Rack 1 = aa
Number of bananas in Rack 2 = aa
Total number of bananas = a+a=2aa + a = 2a.

Number of oranges in Rack 1 = bb
Number of oranges in Rack 2 = bb
Total number of oranges = b+b=2bb + b = 2b.

The total number of fruits in the store is the sum of total bananas and total oranges.
Total fruits = 2a+2b2a + 2b.
This expression can be simplified by factoring out the common factor of 2.
Total fruits = 2(a+b)2(a+b).
The simplified expression for the total number of fruits is 2(a+b)\boxed{2(a+b)}.

13. A carpenter at Gikomba furniture shop is making a rectangular table top. The length is (x+5)(x+5) cm and the width is (x−2)(x-2) cm. Form a simplified expression for the area of the table top.

The area of a rectangle is given by the formula A=length×widthA = \text{length} \times \text{width}.
Given:
Length L=(x+5)L = (x+5) cm
Width W=(x−2)W = (x-2) cm

Substitute these into the area formula:

A=(x+5)(x−2)A = (x+5)(x-2)

Expand the expression by multiplying the terms:

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