We read your photo as:

Please solve the following word problems: 1. It takes 9 minutes to walk around the school field once. How long does it take to walk around the school 7 times? 2. I have six water tanks. Each tank hold

Mathematics

ScanSolve AI Answer

Answers

6 parts
1

63 minutes\text{63 minutes}

2

9000 litres\text{9000 litres}

3

19 m\frac{1}{9} \text{ m}

a

0.6 mol\text{0.6 mol}

b

0.05 mol\text{0.05 mol}

c

12.96 mol\text{12.96 mol}

Step-by-step solution

13 steps

Here are the solutions to your questions:

Part 1· 2 steps

It takes 9 minutes to walk around the school field once. How long does it take to walk around the school 7 times?

  1. Identify the given values.

    Time for one round =9 minutes= 9 \text{ minutes}
    Number of rounds =7= 7

  2. Calculate the total time.

    Total time == Time for one round ×\times Number of rounds

    Total time=9 minutes×7\text{Total time} = 9 \text{ minutes} \times 7 Total time=63 minutes\text{Total time} = 63 \text{ minutes}

    The total time taken is 63 minutes\boxed{\text{63 minutes}}.

Part 2

9000 litres\text{9000 litres}

I have six water tanks. Each tank holds 1500 litres of water. How many litres of water can my tanks hold?

  1. Identify the given values.

    Number of tanks =6= 6
    Volume per tank =1500 litres= 1500 \text{ litres}

  2. Calculate the total volume.

    Total volume == Number of tanks ×\times Volume per tank

    Total volume=6×1500 litres\text{Total volume} = 6 \times 1500 \text{ litres} Total volume=9000 litres\text{Total volume} = 9000 \text{ litres}

    The tanks can hold a total of 9000 litres\boxed{\text{9000 litres}} of water.

Part 3

19 m\frac{1}{9} \text{ m}

A rectangular tank has a volume of 7 m³. It is 9 m wide and 7 m high. Find the length of the tank.

  1. Write down the formula for the volume of a rectangular tank.

    The volume VV of a rectangular tank is given by:

    V=length×width×heightV = \text{length} \times \text{width} \times \text{height} V=L×W×HV = L \times W \times H

  2. Substitute the given values into the formula.

    Given: V=7 m3V = 7 \text{ m}^3, W=9 mW = 9 \text{ m}, H=7 mH = 7 \text{ m}.

    7 m3=L×9 m×7 m7 \text{ m}^3 = L \times 9 \text{ m} \times 7 \text{ m}

  3. Solve for the length LL.

    7 m3=L×63 m27 \text{ m}^3 = L \times 63 \text{ m}^2 L=7 m363 m2L = \frac{7 \text{ m}^3}{63 \text{ m}^2} L=19 mL = \frac{1}{9} \text{ m}

    The length of the tank is 19 m\boxed{\frac{1}{9} \text{ m}}.

Part 4

Study the cuboid below. Its volume is 4536 m³. Find its width.

To find the width of the cuboid, we need its length and height. The image of the cuboid with these dimensions is not provided. Please provide the image or the length and height values.

Part 5

Calculate the number of moles in the solution.

The formula for the number of moles (nn) is:

n=Molarity(M)×Volume(V in litres)n = \text{Molarity} (M) \times \text{Volume} (V \text{ in litres})

Part a

0.6 mol\text{0.6 mol}

750 cm³ of 0.8 M solution

  1. Convert the volume from cm³ to litres.

    V=750 cm3=7501000 L=0.750 LV = 750 \text{ cm}^3 = \frac{750}{1000} \text{ L} = 0.750 \text{ L}

  2. Calculate the number of moles.

    n=0.8 M×0.750 Ln = 0.8 \text{ M} \times 0.750 \text{ L} n=0.6 moln = 0.6 \text{ mol}

    The number of moles is 0.6 mol\boxed{\text{0.6 mol}}.

Part b

0.05 mol\text{0.05 mol}

100 cm³ of 0.5 M solution

  1. Convert the volume from cm³ to litres.

    V=100 cm3=1001000 L=0.100 LV = 100 \text{ cm}^3 = \frac{100}{1000} \text{ L} = 0.100 \text{ L}

  2. Calculate the number of moles.

    n=0.5 M×0.100 Ln = 0.5 \text{ M} \times 0.100 \text{ L} n=0.05 moln = 0.05 \text{ mol}

    The number of moles is 0.05 mol\boxed{\text{0.05 mol}}.

Part c

12.96 mol\text{12.96 mol}

54 litres of 0.24 M solution

  1. The volume is already in litres.

    V=54 LV = 54 \text{ L}

  2. Calculate the number of moles.

    n=0.24 M×54 Ln = 0.24 \text{ M} \times 54 \text{ L} n=12.96 moln = 12.96 \text{ mol}

    The number of moles is 12.96 mol\boxed{\text{12.96 mol}}.

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question

More Mathematics Questions

QSolve the following word problems involving fractions: 1. Alan jogged 5/8 km. He jogged 1/4 km more…QSolve the following word problems: 1. Michael took 1 1/4 hours to do his homework. Henry took 1/2…QSolve the following multiplication problems and word problems.QSolve the following word problems involving algebra and fractions.QSolve the following word problems involving simple algebraic equations:
See all Mathematics questions →
Got a syllabus? Photograph it and I'll tell you what's due and what's worth the most.
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp