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Solve the following word problems involving fractions: 1. Alan jogged 5/8 km. He jogged 1/4 km more than Aiden. How far did Aiden jog? 2. Mrs Davies prepared 4/5 litre of apple juice. The next day, th

Mathematics

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Here are the solutions to the word problems:

:
Alan jogged 58\frac{5}{8} kilometre. He jogged 14\frac{1}{4} kilometre more than Aiden. How far did Aiden jog?

  1. Identify the operation needed.

    Since Alan jogged 14\frac{1}{4} km more than Aiden, Aiden jogged 14\frac{1}{4} km less than Alan. We need to subtract the difference from Alan's distance.

    Aiden’s distance=58−14\text{Aiden's distance} = \frac{5}{8} - \frac{1}{4}
  2. Find a common denominator for the fractions.

    The least common multiple of 8 and 4 is 8. Convert 14\frac{1}{4} to an equivalent fraction with a denominator of 8.

    14=1×24×2=28\frac{1}{4} = \frac{1 \times 2}{4 \times 2} = \frac{2}{8}
  3. Perform the subtraction.

    58−28=5−28=38\frac{5}{8} - \frac{2}{8} = \frac{5-2}{8} = \frac{3}{8}

    Aiden jogged 38\frac{3}{8} kilometre.

    The distance Aiden jogged is 38 km\boxed{\frac{3}{8} \text{ km}}.

    :
    Mrs Davies prepared 45\frac{4}{5} litre of apple juice. The next day, there were 310\frac{3}{10} litre of apple juice left. How many litres of apple juice were drunk?

  4. Identify the operation needed.

    To find out how much juice was drunk, we subtract the amount left from the initial amount.

    Amount drunk=45−310\text{Amount drunk} = \frac{4}{5} - \frac{3}{10}
  5. Find a common denominator for the fractions.

    The least common multiple of 5 and 10 is 10. Convert 45\frac{4}{5} to an equivalent fraction with a denominator of 10.

    45=4×25×2=810\frac{4}{5} = \frac{4 \times 2}{5 \times 2} = \frac{8}{10}
  6. Perform the subtraction.

    810−310=8−310=510\frac{8}{10} - \frac{3}{10} = \frac{8-3}{10} = \frac{5}{10}
  7. Simplify the fraction.

    510=12\frac{5}{10} = \frac{1}{2}

    Mrs Davies' family drank 12\frac{1}{2} litre of apple juice.

    The amount of apple juice drunk is 12 litre\boxed{\frac{1}{2} \text{ litre}}.

    :
    Jessica took 56\frac{5}{6} hour to complete her homework. She took another 34\frac{3}{4} hour to revise for her test. How many hours did Jessica put in to complete her homework and revise for her test?

  8. Identify the operation needed.

    To find the total time Jessica spent, we need to add the time for homework and the time for revision.

    Total time=56+34\text{Total time} = \frac{5}{6} + \frac{3}{4}
  9. Find a common denominator for the fractions.

    The least common multiple of 6 and 4 is 12. Convert both fractions to equivalent fractions with a denominator of 12.

    56=5×26×2=1012\frac{5}{6} = \frac{5 \times 2}{6 \times 2} = \frac{10}{12} 34=3×34×3=912\frac{3}{4} = \frac{3 \times 3}{4 \times 3} = \frac{9}{12}
  10. Perform the addition.

    1012+912=10+912=1912\frac{10}{12} + \frac{9}{12} = \frac{10+9}{12} = \frac{19}{12}

    Jessica put in 1912\frac{19}{12} hours.

    The total hours Jessica put in is 1912 hours\boxed{\frac{19}{12} \text{ hours}}.

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