Solve the following word problems: 1. Nyambura is three times as old as Halima. The sum of their ages is 36. How old is Nyambura? 2. In a classroom, there are 2 more boys than girls. There are 10 fewe

Let Halima's age be $H$ years.
Let Nyambura's age be $N$ years.
From the problem:
$N = 3H$ (Nyambura is three times as old as Halima)
$N + H = 36$ (The sum of their ages is 36)

Substitute $N = 3H$ into $N + H = 36$:

Nyambura is 27 years old.

2. Classroom Numbers

Let the number of girls be $G$.
Let the number of boys be $B$.
Let the number of teachers be $T$.
From the problem:
$B = G + 2$ (Boys are 2 more than girls)
$T = B - 10$ (Teachers are 10 less than boys)
$B + G + T = 27$ (Total people in class)

Substitute $B = G + 2$ into $T = B - 10$:

There are 13 boys, 11 girls, and 3 teachers.

3. Consecutive Numbers

Let the first number be $x$.
The second number is $x + 1$.
The third number is $x + 2$.

First number: 23
Second number: $23 + 1 = 24$
Third number: $23 + 2 = 25$
The three consecutive numbers are 23, 24, and 25.

4. Price of Trousers and Shirt

Let the price of a shirt be $S$.
Let the price of a pair of trousers be $T$.
From the problem:
$T = 2S$ (Trousers are twice the price of a shirt)
$T + S = 1200$ (Total cost is sh 1 200)

Substitute $T = 2S$ into $T + S = 1200$:

The price of the shirt is sh 400.

5. Farmer's Animals

Let the number of sheep be $S$.
Let the number of goats be $G$.
Let the number of cows be $C$.
From the problem:
$G = S + 15$ (15 more goats than sheep)
$C = 3S$ (3 times as many cows as sheep)
$S + G + C = 75$ (Total animals)

$G = S + 15$
$C = 3S$

The farmer has 36 cows.