For each diagram, find: the bearing of P from Q.

a) Find the bearing of P from Q.

1. Diagram 1:
The bearing of Q from P is $075^\circ$.
To find the bearing of P from Q, we use the rule: if the bearing is less than $180^\circ$, add $180^\circ$.

$$\text{Bearing of P from Q} = 075^\circ + 180^\circ = 255^\circ$$

The bearing of P from Q is $\boxed{\text{255}^\circ}$.

2. Diagram 2:
The bearing of Q from P is $250^\circ$.
To find the bearing of P from Q, we use the rule: if the bearing is greater than $180^\circ$, subtract $180^\circ$.

$$\text{Bearing of P from Q} = 250^\circ - 180^\circ = 070^\circ$$

The bearing of P from Q is $\boxed{\text{070}^\circ}$.

b) Find the bearing of Q from P.

3. Diagram 3:
The bearing of Q from P is given as $130^\circ$.
(Assuming the question intends for us to find the reverse bearing, i.e., the bearing of P from Q, as is common in these exercises and consistent with part a). If it literally means "find the bearing of Q from P" when it's already given, the answer is simply $130^\circ$. I will proceed with finding the bearing of P from Q.)
The bearing of Q from P is $130^\circ$.
To find the bearing of P from Q, we use the rule: if the bearing is less than $180^\circ$, add $180^\circ$.

$$\text{Bearing of P from Q} = 130^\circ + 180^\circ = 310^\circ$$

The bearing of P from Q is $\boxed{\text{310}^\circ}$.

4. Diagram 4:
The diagram shows the bearing of P from Q is $085^\circ$.
To find the bearing of Q from P, we use the rule: if the bearing is less than $180^\circ$, add $180^\circ$.

$$\text{Bearing of Q from P} = 085^\circ + 180^\circ = 265^\circ$$

The bearing of Q from P is $\boxed{\text{265}^\circ}$.