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Solve for the following algebraic expressions by substitution and expansion of brackets.

Mathematics

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Step-by-step solution

28 steps

Here are the solutions to the problems.

Part 1

Substitution

Part 1.1· 4 steps

  1. Substitute x=3x=3 into the expression 2(x+4)22(x+4)^2.

    2(3+4)22(3+4)^2
  2. Perform the operation inside the parenthesis.

    2(7)22(7)^2
  3. Calculate the square.

    2(49)2(49)
  4. Multiply.

    9898

    The value is:

    98\boxed{98}

Part 1.2· 3 steps

  1. Substitute x=8x=8 and y=9y=9 into the expression x+73y\frac{\sqrt[3]{x+7}}{\sqrt{y}}.

    8+739\frac{\sqrt[3]{8+7}}{\sqrt{9}}
  2. Simplify the terms under the radicals.

    1539\frac{\sqrt[3]{15}}{\sqrt{9}}
  3. Calculate the cube root and the square root.

    1533\frac{\sqrt[3]{15}}{3}

    The value is:

    1533\boxed{\frac{\sqrt[3]{15}}{3}}

Part 1.3· 4 steps

  1. Substitute x=2x=2 and y=3y=3 into the expression 6x4y2−18x3y3+12x2y6x^4y^2 - 18x^3y^3 + 12x^2y.

    6(2)4(3)2−18(2)3(3)3+12(2)2(3)6(2)^4(3)^2 - 18(2)^3(3)^3 + 12(2)^2(3)
  2. Calculate the powers.

    6(16)(9)−18(8)(27)+12(4)(3)6(16)(9) - 18(8)(27) + 12(4)(3)
  3. Perform the multiplications in each term.

    864−3888+144864 - 3888 + 144
  4. Perform the additions and subtractions.

    −3024+144-3024 + 144 −2880-2880

    The value is:

    −2880\boxed{-2880}

Part 2

Expanding Brackets

Part 2.1· 2 steps

  1. Expand the product (x+4)(x−3)(x+4)(x-3) using the FOIL method (First, Outer, Inner, Last).

    x⋅x+x⋅(−3)+4⋅x+4⋅(−3)x \cdot x + x \cdot (-3) + 4 \cdot x + 4 \cdot (-3) x2−3x+4x−12x^2 - 3x + 4x - 12
  2. Combine like terms.

    x2+x−12x^2 + x - 12

    The expanded expression is:

    x2+x−12\boxed{x^2+x-12}

Part 2.2· 1 step

  1. Distribute x2x^2 to each term inside the parenthesis (2x−4)(2x-4).

    x2(2x)−x2(4)x^2(2x) - x^2(4) 2x3−4x22x^3 - 4x^2

    The expanded expression is:

    2x3−4x2\boxed{2x^3-4x^2}

Part 3

Factorize the following expressions

Part 3.1· 2 steps

  1. Find the greatest common factor (GCF) of x2x^2 and 4x4x.

    The GCF is xx.

  2. Factor out the GCF.

    x(x+4)x(x+4)

    The factored expression is:

    x(x+4)\boxed{x(x+4)}

Part 3.2· 2 steps

  1. Find the GCF of 25xy225xy^2 and 15x2y15x^2y.

    The GCF of 25 and 15 is 5.
    The GCF of xx and x2x^2 is xx.
    The GCF of y2y^2 and yy is yy.
    So, the overall GCF is 5xy5xy.

  2. Factor out the GCF.

    5xy(5y+3x)5xy(5y + 3x)

    The factored expression is:

    5xy(5y+3x)\boxed{5xy(5y+3x)}

Part 3.3· 2 steps

  1. Find the GCF of 8x3y28x^3y^2 and 12x2y312x^2y^3.

    The GCF of 8 and 12 is 4.
    The GCF of x3x^3 and x2x^2 is x2x^2.
    The GCF of y2y^2 and y3y^3 is y2y^2.
    So, the overall GCF is 4x2y24x^2y^2.

  2. Factor out the GCF.

    4x2y2(2x−3y)4x^2y^2(2x - 3y)

    The factored expression is:

    4x2y2(2x−3y)\boxed{4x^2y^2(2x-3y)}

Part 3.4· 1 step

  1. Factor the quadratic expression x2−x−12x^2-x-12.

    We need two numbers that multiply to −12-12 and add to −1-1. These numbers are 3 and −4-4.

    (x+3)(x−4)(x+3)(x-4)

    The factored expression is:

    (x+3)(x−4)\boxed{(x+3)(x-4)}

Part 3.5· 2 steps

  1. Find the GCF of 6x4y26x^4y^2, −18x3y3-18x^3y^3, and 12x2y12x^2y.

    The GCF of 6, 18, and 12 is 6.
    The GCF of x4x^4, x3x^3, and x2x^2 is x2x^2.
    The GCF of y2y^2, y3y^3, and yy is yy.
    So, the overall GCF is 6x2y6x^2y.

  2. Factor out the GCF.

    6x2y(x2y−3xy2+2)6x^2y(x^2y - 3xy^2 + 2)

    The factored expression is:

    6x2y(x2y−3xy2+2)\boxed{6x^2y(x^2y-3xy^2+2)}

Part 3.6· 1 step

  1. Factor the quadratic expression x2−9x+20x^2-9x+20.

    We need two numbers that multiply to 20 and add to −9-9. These numbers are −4-4 and −5-5.

    (x−4)(x−5)(x-4)(x-5)

    The factored expression is:

    (x−4)(x−5)\boxed{(x-4)(x-5)}

Part 3.7· 4 steps

  1. Subtract x2−4x−5x^2-4x-5 from 2x2+x−12x^2+x-1.

    (2x2+x−1)−(x2−4x−5)(2x^2+x-1) - (x^2-4x-5)
  2. Distribute the negative sign.

    2x2+x−1−x2+4x+52x^2+x-1 - x^2+4x+5
  3. Combine like terms.

    (2x2−x2)+(x+4x)+(−1+5)(2x^2-x^2) + (x+4x) + (-1+5) x2+5x+4x^2 + 5x + 4
  4. Factor the resulting quadratic expression x2+5x+4x^2+5x+4.

    We need two numbers that multiply to 4 and add to 5. These numbers are 1 and 4.

    (x+1)(x+4)(x+1)(x+4)

    The factored expression is:

    (x+1)(x+4)\boxed{(x+1)(x+4)}
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