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Solve for x: 5 1/4 + x = 7 2/5

Mathematics

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Answer

23202 \frac{3}{20}

Step-by-step solution

6 steps
  1. Represent the problem as an equation.

    Let the unknown number be xx.

    514+x=7255 \frac{1}{4} + x = 7 \frac{2}{5}
  2. Convert the mixed fractions to improper fractions.

    514=(5×4)+14=20+14=2145 \frac{1}{4} = \frac{(5 \times 4) + 1}{4} = \frac{20 + 1}{4} = \frac{21}{4} 725=(7×5)+25=35+25=3757 \frac{2}{5} = \frac{(7 \times 5) + 2}{5} = \frac{35 + 2}{5} = \frac{37}{5}
  3. Rewrite the equation with improper fractions and solve for xx.

    214+x=375\frac{21}{4} + x = \frac{37}{5}

    To find xx, subtract 214\frac{21}{4} from 375\frac{37}{5}:

    x=375−214x = \frac{37}{5} - \frac{21}{4}
  4. Find a common denominator for the fractions.

    The least common multiple of 5 and 4 is 20.
    Convert both fractions to have a denominator of 20:

    375=37×45×4=14820\frac{37}{5} = \frac{37 \times 4}{5 \times 4} = \frac{148}{20} 214=21×54×5=10520\frac{21}{4} = \frac{21 \times 5}{4 \times 5} = \frac{105}{20}
  5. Perform the subtraction.

    x=14820−10520x = \frac{148}{20} - \frac{105}{20} x=148−10520x = \frac{148 - 105}{20} x=4320x = \frac{43}{20}
  6. Convert the improper fraction back to a mixed number.

    Divide 43 by 20:

    43÷20=2 with a remainder of 343 \div 20 = 2 \text{ with a remainder of } 3

    So, x=2320x = 2 \frac{3}{20}.

    The number that should be added is 23202 \frac{3}{20}.

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