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Four interior angles of an irregular polygon are 163°, 130°, 137°, and 165° while the rest are 133° each. Find the number of sides of the polygon.

Mathematics

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Answer

n=9n = 9

Step-by-step solution

6 steps

Hapa kuna hatua za kutatua swali la 13:

Swali la 13: Pembe nne za ndani za poligoni isiyo ya kawaida ni 163∘,130∘,137∘163^\circ, 130^\circ, 137^\circ, na 165∘165^\circ huku zingine zikiwa 133∘133^\circ kila moja. Tafuta idadi ya pande za poligoni.

  1. Andika fomula ya jumla ya pembe za ndani za poligoni yenye pande nn.

    Jumla ya pembe za ndani za poligoni ni S=(n−2)×180∘S = (n-2) \times 180^\circ.

  2. Kokotoa jumla ya pembe nne zilizotolewa.

    Jumla ya pembe nne = 163∘+130∘+137∘+165∘=595∘163^\circ + 130^\circ + 137^\circ + 165^\circ = 595^\circ.

  3. Eleza jumla ya pembe zilizobaki.

    Ikiwa kuna pande nn, basi kuna pembe nn. Pembe nne zimetolewa, kwa hivyo pembe zilizobaki ni n−4n-4. Kila moja ya pembe hizi ni 133∘133^\circ.
    Jumla ya pembe zilizobaki = (n−4)×133∘(n-4) \times 133^\circ.

  4. Sawazisha jumla ya pembe zote na fomula ya jumla ya pembe za ndani.

    595∘+(n−4)×133∘=(n−2)×180∘595^\circ + (n-4) \times 133^\circ = (n-2) \times 180^\circ
  5. Panua na kurahisisha mlinganyo.

    595+133n−(4×133)=180n−(2×180)595 + 133n - (4 \times 133) = 180n - (2 \times 180) 595+133n−532=180n−360595 + 133n - 532 = 180n - 360 63+133n=180n−36063 + 133n = 180n - 360
  6. Tatua kwa nn.

    Kusanya maneno ya nn upande mmoja na nambari upande mwingine.

    360+63=180n−133n360 + 63 = 180n - 133n 423=47n423 = 47n n=42347n = \frac{423}{47} n=9n = 9

    Idadi ya pande za poligoni ni 9.

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