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Given matrices G = [[6, 0], [-4, 2]] and H = [[9, 0], [-6, 3]], prove or disprove that 5G − 2H = 0.

Mathematics

ScanSolve AI Answer

Step-by-step solution

3 steps
  1. Calculate $5G$.

    Multiply each element of matrix GG by 5.

    5G=5[60−42]=[5×65×05×(−4)5×2]=[300−2010]5G = 5 \begin{bmatrix} 6 & 0 \\ -4 & 2 \end{bmatrix} = \begin{bmatrix} 5 \times 6 & 5 \times 0 \\ 5 \times (-4) & 5 \times 2 \end{bmatrix} = \begin{bmatrix} 30 & 0 \\ -20 & 10 \end{bmatrix}
  2. Calculate $2H$.

    Multiply each element of matrix HH by 2.

    2H=2[90−63]=[2×92×02×(−6)2×3]=[180−126]2H = 2 \begin{bmatrix} 9 & 0 \\ -6 & 3 \end{bmatrix} = \begin{bmatrix} 2 \times 9 & 2 \times 0 \\ 2 \times (-6) & 2 \times 3 \end{bmatrix} = \begin{bmatrix} 18 & 0 \\ -12 & 6 \end{bmatrix}
  3. Calculate 5G−2H5G - 2H.

    Subtract the corresponding elements of 2H2H from 5G5G.

    5G−2H=[300−2010]−[180−126]5G - 2H = \begin{bmatrix} 30 & 0 \\ -20 & 10 \end{bmatrix} - \begin{bmatrix} 18 & 0 \\ -12 & 6 \end{bmatrix} 5G−2H=[30−180−0−20−(−12)10−6]5G - 2H = \begin{bmatrix} 30 - 18 & 0 - 0 \\ -20 - (-12) & 10 - 6 \end{bmatrix} 5G−2H=[120−20+124]5G - 2H = \begin{bmatrix} 12 & 0 \\ -20 + 12 & 4 \end{bmatrix} 5G−2H=[120−84]5G - 2H = \begin{bmatrix} 12 & 0 \\ -8 & 4 \end{bmatrix}

    The problem asks to show that 5G−2H=05G - 2H = 0. However, our calculation shows that 5G−2H=[120−84]5G - 2H = \begin{bmatrix} 12 & 0 \\ -8 & 4 \end{bmatrix}, which is not the zero matrix [0000]\begin{bmatrix} 0 & 0 \\ 0 & 0 \end{bmatrix}.

    Therefore, the statement 5G−2H=05G - 2H = 0 is incorrect based on the given matrices.

    The final answer is The statement 5G−2H=0 is incorrect. 5G−2H=[120−84]\boxed{\text{The statement } 5G - 2H = 0 \text{ is incorrect. } 5G - 2H = \begin{bmatrix} 12 & 0 \\ -8 & 4 \end{bmatrix}}.

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