Step 1: Identify the given matrices M and N.
M=14−33522−10N=142−2−1−335−1
Step 2: Calculate 2M.
Multiply each element of matrix M by 2:
2M=214−33522−10=2×12×42×(−3)2×32×52×22×22×(−1)2×02M=28−661044−20
Step 3: Calculate 3N.
Multiply each element of matrix N by 3:
3N=3142−2−1−335−1=3×13×43×23×(−2)3×(−1)3×(−3)3×33×53×(−1)3N=3126−6−3−9915−3
Step 4: Evaluate 2M−3N.
Subtract the corresponding elements of 3N from 2M:
2M−3N=28−661044−20−3126−6−3−9915−32M−3N=2−38−12−6−66−(−6)10−(−3)4−(−9)4−9−2−150−(−3)2M−3N=−1−4−126+610+34+9−5−170+32M−3N=−1−4−12121313−5−173
Step 5: Compare the result with the given options.
The calculated matrix matches option D.
The final answer is −1−4−12121313−5−173.
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This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.