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Given position vectors of M, N, R from the origin are m, n, and r respectively. R is on MN such that MR = 1/4 RN. Find an expression for r in terms of m and n.

Mathematics

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Answer

r=4m+n5\mathbf{r} = \frac{4\mathbf{m} + \mathbf{n}}{5}

Step-by-step solution

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Here's the solution for the first problem involving position vectors.

: Position Vectors

Given:

  • Position vectors of M, N, R from the origin are m\mathbf{m}, n\mathbf{n}, and r\mathbf{r} respectively.
  • R is a point on MN such that MR⃗=14RN⃗\vec{MR} = \frac{1}{4} \vec{RN}.
  • Find an expression for r\mathbf{r} in terms of m\mathbf{m} and n\mathbf{n}.
  1. Express the vectors MR⃗\vec{MR} and RN⃗\vec{RN} in terms of position vectors.

    The vector from point A to point B is given by AB⃗=OB⃗−OA⃗\vec{AB} = \vec{OB} - \vec{OA}, where OA⃗\vec{OA} and OB⃗\vec{OB} are the position vectors of A and B from the origin.

    MR⃗=OR⃗−OM⃗=r−m\vec{MR} = \vec{OR} - \vec{OM} = \mathbf{r} - \mathbf{m} RN⃗=ON⃗−OR⃗=n−r\vec{RN} = \vec{ON} - \vec{OR} = \mathbf{n} - \mathbf{r}
  2. Substitute these expressions into the given relationship.

    The problem states that MR⃗=14RN⃗\vec{MR} = \frac{1}{4} \vec{RN}.

    r−m=14(n−r)\mathbf{r} - \mathbf{m} = \frac{1}{4} (\mathbf{n} - \mathbf{r})
  3. Solve the equation for r\mathbf{r}.

    First, multiply both sides by 4 to eliminate the fraction:

    4(r−m)=n−r4(\mathbf{r} - \mathbf{m}) = \mathbf{n} - \mathbf{r}

    Distribute the 4 on the left side:

    4r−4m=n−r4\mathbf{r} - 4\mathbf{m} = \mathbf{n} - \mathbf{r}

    Gather all terms involving r\mathbf{r} on one side and other terms on the other side:

    4r+r=n+4m4\mathbf{r} + \mathbf{r} = \mathbf{n} + 4\mathbf{m}

    Combine like terms:

    5r=4m+n5\mathbf{r} = 4\mathbf{m} + \mathbf{n}

    Finally, divide by 5 to isolate r\mathbf{r}:

    r=4m+n5\mathbf{r} = \frac{4\mathbf{m} + \mathbf{n}}{5}

    This can also be written as:

    r=45m+15n\mathbf{r} = \frac{4}{5}\mathbf{m} + \frac{1}{5}\mathbf{n}

    The expression for r\mathbf{r} in terms of m\mathbf{m} and n\mathbf{n} is:

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