Given that PRS = 90^, and from the figure, PRQ = 90^.

Given that $\angle PRS = 90^\circ$, and from the figure, $\angle PRQ = 90^\circ$.
Given $\angle QPR = \angle PSR$.
Since the sum of angles in a triangle is $180^\circ$:
In $\triangle PQR$, $\angle PQR = 180^\circ - 90^\circ - \angle QPR = 90^\circ - \angle QPR$.
In $\triangle PRS$, $\angle RPS = 180^\circ - 90^\circ - \angle PSR = 90^\circ - \angle PSR$.
Since $\angle QPR = \angle PSR$, it follows that $\angle PQR = \angle RPS$.
Therefore, $\triangle PQR$ is similar to $\triangle SPR$ (Angle-Angle-Angle similarity).

Let $PR = 4k$ and $QR = 3k$ for some constant $k$.
The area of $\triangle PQR = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times QR \times PR$.

So, $PR = 4 \times 2 = 8 \text{ cm}$ and $QR = 3 \times 2 = 6 \text{ cm}$.

Since $\triangle PQR \sim \triangle SPR$, the ratio of their areas is:

Using the sides $QR=6$ and $PR=8$:

The area of triangle PRS is $\boxed{42 \frac{2}{3} \text{ cm}^2}$.

6. A suit whose marked price is sh. 8,000 is sold to customer after allowing him a discount of 13%. If the trader makes a profit of 20%, find how much the trader paid for the suit.

Marked Price (MP) = Sh. 8,000.
Discount = 13%.
Discount amount = $13\%$ of $8,000 = 0.13 \times 8,000 = \text{Sh. } 1,040$.
Selling Price (SP) = MP - Discount amount = $8,000 - 1,040 = \text{Sh. } 6,960$.
Alternatively, $SP = MP \times (1 - \text{discount percentage}) = 8,000 \times (1 - 0.13) = 8,000 \times 0.87 = \text{Sh. } 6,960$.

Profit = 20%.
The selling price (SP) is the cost price plus the profit.
$SP = CP + (20\% \text{ of } CP) = CP \times (1 + 0.20) = 1.20 \times CP$.

The trader paid $\boxed{\text{Sh. } 5,800}$ for the suit.

**7. Evans is a salesperson with Ajab Millers. He is paid on monthly basis as the agreement; basic pay of Ksh. 20,000, a commission