Find the nature of roots of 2x2 + 3x + 5 = 0. Give an example for (i) Similar Figures and (ii) Non-Similar Figures.

Mathematics
Find the nature of roots of 2x2 + 3x + 5 = 0. Give an example for (i) Similar Figures and (ii) Non-Similar Figures.

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Answer

70\text{70}^\circ

Step 1: Identify the properties of tangents and radii. Given that TP and TQ are tangents to a circle with center O, the radii OP and OQ are perpendicular to the tangents at the points of tangency P and Q, respectively. Therefore, we have: OPT=90\angle OPT = 90^\circ OQT=90\angle OQT = 90^\circ

Step 2: Use the sum of angles in a quadrilateral. The points O, P, T, and Q form a quadrilateral OPTQ. The sum of the interior angles of a quadrilateral is 360360^\circ. So, we can write the equation: OPT+PTQ+OQT+POQ=360\angle OPT + \angle PTQ + \angle OQT + \angle POQ = 360^\circ

Step 3: Substitute the known values into the equation. We are given POQ=110\angle POQ = 110^\circ. Substituting the known angles: 90+PTQ+90+110=36090^\circ + \angle PTQ + 90^\circ + 110^\circ = 360^\circ

Step 4: Solve for PTQ\angle PTQ. Combine the constant terms: 290+PTQ=360290^\circ + \angle PTQ = 360^\circ Subtract 290290^\circ from both sides: PTQ=360290\angle PTQ = 360^\circ - 290^\circ PTQ=70\angle PTQ = 70^\circ

The value of PTQ\angle PTQ is 70\boxed{70^\circ}.

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Quick Answer

Identify the properties of tangents and radii. Given that TP and TQ are tangents to a circle with center O, the radii OP and OQ are perpendicular to the tangents at the points of tangency P and Q, respectively.

Find the nature of roots of 2x2 + 3x + 5 = 0. Give an example for (i) Similar Figures and (ii) Non-Similar Figures.
Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI Answer
Step 1: Identify the properties of tangents and radii. Given that TP and TQ are tangents to a circle with center O, the radii OP and OQ are perpendicular to the tangents at the points of tangency P and Q, respectively. Therefore, we have: OPT = 90^ OQT = 90^ Step 2: Use the sum of angles in a quadrilateral. The points O, P, T, and Q form a quadrilateral OPTQ. The sum of the interior angles of a quadrilateral is 360^. So, we can write the equation: OPT + PTQ + OQT + POQ = 360^ Step 3: Substitute the known values into the equation. We are given POQ = 110^. Substituting the known angles: 90^ + PTQ + 90^ + 110^ = 360^ Step 4: Solve for PTQ. Combine the constant terms: 290^ + PTQ = 360^ Subtract 290^ from both sides: PTQ = 360^ - 290^ PTQ = 70^ The value of PTQ is 70^.