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Given the relation C = (3)/(2) sqrt(f2 + 4P2Q), express f in terms of C, P, and Q.

Mathematics

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Answer

f=±2C2−9P2Q3f = \pm \frac{2\sqrt{C^2 - 9P^2Q}}{3}

Step-by-step solution

7 steps

Given the relation:

C=32f2+4P2QC = \frac{3}{2} \sqrt{f^2 + 4P^2Q}

We need to express ff in terms of CC, PP, and QQ.

  1. Multiply both sides by 2.

    2C=3f2+4P2Q2C = 3 \sqrt{f^2 + 4P^2Q}
  2. Divide both sides by 3.

    2C3=f2+4P2Q\frac{2C}{3} = \sqrt{f^2 + 4P^2Q}
  3. Square both sides to eliminate the square root.

    (2C3)2=f2+4P2Q\left(\frac{2C}{3}\right)^2 = f^2 + 4P^2Q 4C29=f2+4P2Q\frac{4C^2}{9} = f^2 + 4P^2Q
  4. Subtract 4P2Q4P^2Q from both sides to isolate f2f^2.

    f2=4C29−4P2Qf^2 = \frac{4C^2}{9} - 4P^2Q
  5. Combine the terms on the right side by finding a common denominator.

    f2=4C29−36P2Q9f^2 = \frac{4C^2}{9} - \frac{36P^2Q}{9} f2=4C2−36P2Q9f^2 = \frac{4C^2 - 36P^2Q}{9}
  6. Take the square root of both sides to solve for ff.

    f=±4C2−36P2Q9f = \pm \sqrt{\frac{4C^2 - 36P^2Q}{9}}
  7. Simplify the expression by taking the square root of the denominator and factoring out 4 from the numerator inside the square root.

    f=±4(C2−9P2Q)9f = \pm \frac{\sqrt{4(C^2 - 9P^2Q)}}{\sqrt{9}} f=±2C2−9P2Q3f = \pm \frac{2\sqrt{C^2 - 9P^2Q}}{3}
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