Evaluate the given trigonometric expression: (sin 30 + tan 45 - csc 60) / (sec 30 + cos 60 + cot 45)

We know:
$\sin 30^\circ = \frac{1}{2}$
$\tan 45^\circ = 1$
$\csc 60^\circ = \frac{2}{\sqrt{3}}$
$\sec 30^\circ = \frac{2}{\sqrt{3}}$
$\cos 60^\circ = \frac{1}{2}$
$\cot 45^\circ = 1$

Substituting these values into the expression:

Multiply the numerator and denominator by the conjugate of the denominator, which is $3\sqrt{3} - 4$.

The final answer is $\boxed{\frac{43 - 24\sqrt{3}}{11}}$.

:
Evaluate $\frac{5 \cos^2 60^\circ + 4 \sec^2 30^\circ - \tan^2 45^\circ}{\sin^2 30^\circ + \cos^2 30^\circ}$

We know:
$\cos 60^\circ = \frac{1}{2}$
$\sec 30^\circ = \frac{2}{\sqrt{3}}$
$\tan 45^\circ = 1$
And by the Pythagorean identity, $\sin^2 \theta + \cos^2 \theta = 1$, so $\sin^2 30^\circ + \cos^2 30^\circ = 1$.

The common denominator for 4 and 3 is 12.

The final answer is $\boxed{\frac{67}{12}}$.