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Gradient describes the "steepness" of the line and is linked to the constant differences you studied in Numeric Patterns. Task 4.1: Trend Analysis [3 Marks] Categorize each line as Increasing, Decreasing, or Constant.

Mathematics

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here are the solutions for the remaining tasks.

Phase 4: Investigating Gradient (Rate of Change) [10 Marks]

Task 4.1: Trend Analysis [3 Marks]

EquationTrend
1. y=12x+2y = \frac{1}{2}x + 2Increasing
2. y=2x−4y = 2x - 4Increasing
3. y=−2x+2y = -2x + 2Decreasing

Task 4.2: Guided Discovery (Constant Difference) [4 Marks]

  • Change in y:
  1. From the table for Equation 2 (y=2x−4y = 2x - 4), select two consecutive x-values that differ by 1, for example, x=0x=0 and x=1x=1.

    When $x=0$, $y = 2(0) - 4 = -4$.  
    When $x=1$, $y = 2(1) - 4 = -2$.
    
  2. Calculate the difference in y-values.

    $$
    \text{Change in y} = y_{x=1} - y_{x=0} = -2 - (-4)
    $$
    $$
    \text{Change in y} = -2 + 4
    $$
    $$
    \text{Change in y} = \boxed{2}
    $$
    

    Task 4.3: Connecting Equation to Slope [3 Marks]

    • Observation: The "change in y" calculated in Task 4.2 is 2. The coefficient of xx in the original equation y=2x−4y = 2x - 4 is also 2. This shows that the coefficient of xx (the gradient) directly represents the constant change in yy for every unit increase in xx.

    Phase 5: Conclusion and Generalization [8 Marks]

    Task 5.1: The General Rule [3 Marks]

    • The gradient (mm) represents the steepness (or rate of change) of the line.
    • The y-intercept (cc) represents the point where the line crosses the y-axis (or the value of y when x is 0) of the line.
    • The x-intercept is found by setting y to 0.
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