Find the gradient of 4y−x=4÷3

Kwanza, andika upya $4 \div 3$ kama $\frac{4}{3}$:

$$4y - x = \frac{4}{3}$$

$$\frac{4y}{4} = \frac{x}{4} + \frac{\frac{4}{3}}{4}$$ $$y = \frac{1}{4}x + \frac{4}{3 \times 4}$$ $$y = \frac{1}{4}x + \frac{4}{12}$$ $$y = \frac{1}{4}x + \frac{1}{3}$$

Katika mfumo $y = mx + c$, $m$ ni mteremko. Kutoka mlinganyo wetu $y = \frac{1}{4}x + \frac{1}{3}$, tunaona kwamba $m = \frac{1}{4}$.

Mteremko ni $\frac{1}{4}$.