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Hasil dari ((81x3yz2)/(27x2y4z2))4 adalah ....

Mathematics

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Answer

D. 81xy3z4\text{D. } 81xy^3z^4

Step-by-step solution

6 steps

To simplify the expression, we will first simplify the fraction inside the parentheses and then raise the entire result to the power of 4.

  1. Simplify the numerical coefficients.

    8127=3\frac{81}{27} = 3
  2. Simplify the terms with xx using the exponent rule aman=am−n\frac{a^m}{a^n} = a^{m-n}.

    x34−12=x34−24=x14x^{\frac{3}{4} - \frac{1}{2}} = x^{\frac{3}{4} - \frac{2}{4}} = x^{\frac{1}{4}}
  3. Simplify the terms with yy using the exponent rule aman=am−n\frac{a^m}{a^n} = a^{m-n}.

    The exponent of yy in the numerator is 1.

    y1−14=y44−14=y34y^{1 - \frac{1}{4}} = y^{\frac{4}{4} - \frac{1}{4}} = y^{\frac{3}{4}}
  4. Simplify the terms with zz using the exponent rule aman=am−n\frac{a^m}{a^n} = a^{m-n}.

    z32−12=z22=z1=zz^{\frac{3}{2} - \frac{1}{2}} = z^{\frac{2}{2}} = z^1 = z
  5. Combine the simplified terms inside the parentheses.

    (3x14y34z)4\left( 3x^{\frac{1}{4}}y^{\frac{3}{4}}z \right)^4
  6. Apply the outer exponent of 4 to each term inside the parentheses using the rule (abc)n=anbncn(abc)^n = a^n b^n c^n and (am)n=amn(a^m)^n = a^{mn}.

    34(x14)4(y34)4(z)43^4 \left(x^{\frac{1}{4}}\right)^4 \left(y^{\frac{3}{4}}\right)^4 (z)^4 81x14×4y34×4z481 x^{\frac{1}{4} \times 4} y^{\frac{3}{4} \times 4} z^4 81x1y3z481 x^1 y^3 z^4 81xy3z481xy^3z^4

    The simplified expression is 81xy3z481xy^3z^4. This matches option D.

    The final answer is D. 81xy3z4\text{D. } 81xy^3z^4.

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