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Diketahui sistem persamaan 2x − y = 4, 2x + 3z = 14, dan 2y − z + 8 = 0. Berdasarkan sistem persamaan tersebut, persamaan berikut yang bernilai paling besar adalah ...

Mathematics

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To find the expression with the largest value, we first need to solve the given system of linear equations for xx, yy, and zz.

The system of equations is:

  1. 2x−y=42x - y = 4
  2. 2x+3z=142x + 3z = 14
  3. 2y−z+8=0  ⟹  2y−z=−82y - z + 8 = 0 \implies 2y - z = -8
  1. Express yy in terms of xx from equation (1).

    From 2x−y=42x - y = 4, we get y=2x−4y = 2x - 4. (Equation 1a)

  2. Express zz in terms of yy from equation (3).

    From 2y−z=−82y - z = -8, we get z=2y+8z = 2y + 8. (Equation 3a)

  3. Substitute Equation 1a into Equation 3a to express zz in terms of xx.

    z=2(2x−4)+8z = 2(2x - 4) + 8 z=4x−8+8z = 4x - 8 + 8

    z=4xz = 4x (Equation 3b)

  4. Substitute Equation 3b into equation (2) to solve for xx.

    2x+3(4x)=142x + 3(4x) = 14 2x+12x=142x + 12x = 14 14x=1414x = 14 x=1x = 1
  5. Substitute the value of xx back into Equation 1a and Equation 3b to find yy and zz.

    For yy:

    y=2(1)−4y = 2(1) - 4 y=2−4y = 2 - 4 y=−2y = -2

    For zz:

    z=4(1)z = 4(1) z=4z = 4

    So, the solution to the system is x=1x=1, y=−2y=-2, z=4z=4.

  6. Evaluate each given expression using x=1x=1, y=−2y=-2, and z=4z=4.

    A. x+2y=1+2(−2)=1−4=−3x + 2y = 1 + 2(-2) = 1 - 4 = -3
    B. 2y+z=2(−2)+4=−4+4=02y + z = 2(-2) + 4 = -4 + 4 = 0
    C. 2x−3z=2(1)−3(4)=2−12=−102x - 3z = 2(1) - 3(4) = 2 - 12 = -10
    D. 3y+z=3(−2)+4=−6+4=−23y + z = 3(-2) + 4 = -6 + 4 = -2
    E. 3x−z=3(1)−4=3−4=−13x - z = 3(1) - 4 = 3 - 4 = -1

  7. Compare the values to find the largest one.

    The values are -3, 0, -10, -2, and -1. The largest value among these is 0.

    The expression with the largest value is 2y+z2y + z.

    The final answer is B. 2y+z\boxed{\text{B. } 2y + z}.

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