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Mathematics

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Step-by-step solution

6 steps

Part 1

Part a· 1 step

Find the first 5 terms of the sequence defined by a₁ = 3 and aₙ = 2aₙ₋₁ + 1 for n ≥ 2.

  1. Use the given recursive formula to find each term.

    a₁ = 3 (given)
    a₂ = 2a₁ + 1 = 2(3) + 1 = 6 + 1 = 7
    a₃ = 2a₂ + 1 = 2(7) + 1 = 14 + 1 = 15
    a₄ = 2a₃ + 1 = 2(15) + 1 = 30 + 1 = 31
    a₅ = 2a₄ + 1 = 2(31) + 1 = 62 + 1 = 63

    The first 5 terms are 3, 7, 15, 31, 63.

Part b· 2 steps

Is this sequence arithmetic or geometric?

  1. Check for a common difference (arithmetic).

    7 - 3 = 4
    15 - 7 = 8
    Since the difference is not constant, it is not an arithmetic sequence.

  2. Check for a common ratio (geometric).

    7 / 3 ≈ 2.33
    15 / 7 ≈ 2.14
    Since the ratio is not constant, it is not a geometric sequence.

    This sequence is neither arithmetic nor geometric.

Part c· 3 steps

Find a closed-form expression for aₙ.

  1. Observe the pattern in the terms

    3, 7, 15, 31, 63.
    These numbers are close to powers of 2: 4, 8, 16, 32, 64.
    Specifically, each term is 1 less than a power of 2.
    a₁ = 3 = 2² - 1
    a₂ = 7 = 2³ - 1
    a₃ = 15 = 2⁴ - 1
    a₄ = 31 = 2⁵ - 1
    a₅ = 63 = 2⁶ - 1

  2. Identify the relationship between the term number (n) and the exponent.

    The exponent is always n + 1.

  3. Write the closed-form expression.

    The closed-form expression is aₙ = 2^(n+1) - 1.

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