Dry Carbon (II) Oxide gas reacts with heated Lead (II) as shown in the equation below. PbO(s) + CO(g) → CO2(g) + Pb(s) a) Name the process undergone by the Lead (II) Oxide. b) Give a reason for your answer (a) above. c) Name another gas that can be used to perform the same function as Carbon (II) Oxide gas in the above reaction. 2. The diagram below shows a Bunsen burner when in use. d) Name the region labelled C and D.

Chemistry
Dry Carbon (II) Oxide gas reacts with heated Lead (II) as shown in the equation below. PbO(s) + CO(g) → CO2(g) + Pb(s) a) Name the process undergone by the Lead (II) Oxide. b) Give a reason for your answer (a) above. c) Name another gas that can be used to perform the same function as Carbon (II) Oxide gas in the above reaction. 2. The diagram below shows a Bunsen burner when in use. d) Name the region labelled C and D.

ScanSolve AI Answer

1. a) Step 1: Identify the change in Lead (II) Oxide (PbO\text{PbO}). In the reaction PbO(s)+CO(g)CO2(g)+Pb(s)\text{PbO(s)} + CO(g) \rightarrow CO_2(g) + \text{Pb(s)}, Lead (II) Oxide (PbO\text{PbO}) loses oxygen to form Lead (Pb\text{Pb}). Step 2: Define the process. The loss of oxygen is called reduction. The oxidation state of Lead changes from +2 in PbO\text{PbO} to 0 in Pb\text{Pb}, which is a decrease in oxidation state, indicating reduction.

The process undergone by the Lead (II) Oxide is reduction.

b) Reason: Lead (II) Oxide loses oxygen atoms to form Lead metal.

c) Another gas that can be used to perform the same function as Carbon (II) Oxide (a reducing agent) is hydrogen gas (H2\text{H}_2).

2. d) Name the region labelled C and D. C: Non-luminous zone (or Outer zone) D: Luminous zone (or Inner blue cone)

Was this helpful?

Need help with your own homework?

Get instant step-by-step solutions to any question. Free to start.

Ask Your Question

Still have questions?

Quick Answer
  1. a) Step 1: Identify the change in Lead (II) Oxide (PbO).
  2. In the reaction PbO(s) + CO(g) → CO_2(g) + Pb(s), Lead (II) Oxide (PbO) loses oxygen to form Lead (Pb).
  3. The loss of oxygen is called reduction.
  4. The oxidation state of Lead changes from +2 in PbO to 0 in Pb, which is a decrease in oxidation state, indicating reduction.
Dry Carbon (II) Oxide gas reacts with heated Lead (II) as shown in the equation below. PbO(s) + CO(g) → CO2(g) + Pb(s) a) Name the process undergone by the Lead (II) Oxide. b) Give a reason for your answer (a) above. c) Name another gas that can be used to perform the same function as Carbon (II) Oxide gas in the above reaction. 2. The diagram below shows a Bunsen burner when in use. d) Name the region labelled C and D.
Chemistry

This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

ScanSolve AI Answer
1. a) Step 1: Identify the change in Lead (II) Oxide (PbO). In the reaction PbO(s) + CO(g) → CO_2(g) + Pb(s), Lead (II) Oxide (PbO) loses oxygen to form Lead (Pb). Step 2: Define the process. The loss of oxygen is called reduction. The oxidation state of Lead changes from +2 in PbO to 0 in Pb, which is a decrease in oxidation state, indicating reduction. The process undergone by the Lead (II) Oxide is reduction. b) Reason: Lead (II) Oxide loses oxygen atoms to form Lead metal. c) Another gas that can be used to perform the same function as Carbon (II) Oxide (a reducing agent) is hydrogen gas (H_2). 2. d) Name the region labelled C and D. C: Non-luminous zone (or Outer zone) D: Luminous zone (or Inner blue cone)