Here are the solutions to your questions, including corrections for 1.3 and 1.4 based on the correct pole spacing of $1.8 \text{ m}$ from the image. 1.1) Step 1: Identify the given perimeter. The perimeter of the fence is indicated as $2019 \text{ m}$ in the problem statement. The final answer is $\boxed{2019 \text{ m}}$. I noticed an error in my previous calculation for questions 1.3 and 1.4 due to misreading the pole spacing as $4.8 \text{ m}$ instead of the correct $1.8 \text{ m}$. Here are the corrected solutions: 1.3) (Corrected) Step 1: Calculate the number of intervals for the $2019 \text{ m}$ fence with $1.8 \text{ m}$ spacing. $$ \text{Number of intervals} = \frac{\text{Total length}}{\text{Spacing}} = \frac{2019 \text{ m}}{1.8 \text{ m/interval}} = 1121.666... $$ Step 2: Determine the number of poles. For a closed perimeter (like a fence around an area), the number of poles is equal to the number of intervals, rounded up to ensure full coverage. $$ \text{Number of poles} = \lceil 1121.666... \rceil = 1122 \text{ poles} $$ The final answer is $\boxed{1122 \text{ poles}}$. 1.4) (Corrected) Step 1: Calculate the cost if poles are bought in groups of 6 and individually for the remainder. Total poles needed: $1122$. Number of groups of 6: $$ \text{Number of groups} = \frac{1122}{6} = 187 $$ Since $1122$ is perfectly divisible by $6$, $187$ groups of $6$ poles will be bought, with no individual poles. Cost for groups: $187 \times R500 = R93500$. Cost for individual poles: $0 \times R98.00 = R0.00$. Total cost (groups + singles): $R93500 + R0.00 = R93500.00$. Step 2: Calculate the cost if all poles are bought individually. $$ \text{Total cost (individually)} = 1122 \times R98.00 = R109956.00 $$ Step 3: Compare the costs. The cost of buying in groups ($R93500.00$) is less than buying all individually ($R109956.00$). The final answer is $\boxed{R93500.00}$. 3 done, 2 left today. You're making progress.