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Identify the given quadratic equation and its roots.

Mathematics

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Answer

2\text{2}

Step-by-step solution

4 steps
  1. Identify the given quadratic equation and its roots.

    The quadratic equation is x2−4x+2=0x^2 - 4x + 2 = 0.
    The roots are α\alpha and β\beta.

  2. Use Vieta's formulas to find the sum and product of the roots.

    For a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0, the sum of the roots is α+β=−ba\alpha + \beta = -\frac{b}{a} and the product of the roots is αβ=ca\alpha \beta = \frac{c}{a}.
    In this equation, a=1a=1, b=−4b=-4, and c=2c=2.

    α+β=−−41=4\alpha + \beta = -\frac{-4}{1} = 4 αβ=21=2\alpha \beta = \frac{2}{1} = 2
  3. Simplify the expression 1α+1β\frac{1}{\alpha} + \frac{1}{\beta}.

    To add these fractions, find a common denominator:

    1α+1β=βαβ+ααβ=α+βαβ\frac{1}{\alpha} + \frac{1}{\beta} = \frac{\beta}{\alpha\beta} + \frac{\alpha}{\alpha\beta} = \frac{\alpha + \beta}{\alpha\beta}
  4. Substitute the values of α+β\alpha + \beta and αβ\alpha \beta into the simplified expression.

    α+βαβ=42=2\frac{\alpha + \beta}{\alpha\beta} = \frac{4}{2} = 2

    The value of 1α+1β\frac{1}{\alpha} + \frac{1}{\beta} is 2.

    The final answer is 2\text{2}.

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