₹6,000 के मूलधन पर 10% वार्षिक ब्याज की दर से 2 वर्ष का चक्रवृद्धि ब्याज ज्ञात कीजिए।

Step 1: Identify the given values. The principal amount $(P)$ is ₹6,000. The annual rate of interest $(R)$ is $10\%$. The time period $(T)$ is $2$ years.

Step 2: Calculate the effective compound interest rate for 2 years. For two years, the effective compound interest rate can be calculated using the formula: $R_{effective} = \left(R + R + \frac{R \times R}{100}\right)\%$ Substitute $R = 10\%$: $R_{effective} = \left(10 + 10 + \frac{10 \times 10}{100}\right)\%$ $R_{effective} = \left(20 + \frac{100}{100}\right)\%$ $R_{effective} = (20 + 1)\%$ $R_{effective} = 21\%$

Step 3: Calculate the compound interest. Compound Interest (CI) is the principal multiplied by the effective rate. $CI = P \times \frac{R_{effective}}{100}$ $CI = 6000 \times \frac{21}{100}$ $CI = 60 \times 21$ $CI = 1260$

The compound interest is ₹1,260.

The final answer is $\boxed{₹1,260}$.