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Identify the integral expression.

Mathematics

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Answer

xe−t+Cx e^{-t} + C

Step-by-step solution

4 steps
  1. Identify the integral expression.

    The integral to evaluate is given as:

    ∫e−t dx\int e^{-t} \, dx
  2. Determine the variable of integration.

    The differential dxdx indicates that the integration is with respect to xx.

  3. Treat e−te^{-t} as a constant.

    Since tt is not the variable of integration xx, e−te^{-t} is considered a constant during this integration.

  4. Apply the integration rule for a constant.

    The integral of a constant kk with respect to xx is kx+Ckx + C.
    In this case, k=e−tk = e^{-t}.

    ∫e−t dx=e−t∫1 dx=e−t⋅x+C\int e^{-t} \, dx = e^{-t} \int 1 \, dx = e^{-t} \cdot x + C

    The final answer is xe−t+Cx e^{-t} + C.

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