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Identify the polynomial and the divisor.

Mathematics

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Answer

13

Step-by-step solution

5 steps
  1. Identify the polynomial and the divisor.

    The polynomial is f(x)=x4−2x3−6x2−2x+1f(x) = x^4 - 2x^3 - 6x^2 - 2x + 1.
    The divisor is x+2x+2.

  2. Apply the Remainder Theorem.

    The Remainder Theorem states that if a polynomial f(x)f(x) is divided by x−ax-a, the remainder is f(a)f(a).
    In this case, the divisor is x+2x+2, which can be written as x−(−2)x - (-2). So, a=−2a = -2.
    Therefore, the remainder is f(−2)f(-2).

  3. Substitute x=−2x = -2 into the polynomial f(x)f(x).

    f(−2)=(−2)4−2(−2)3−6(−2)2−2(−2)+1f(-2) = (-2)^4 - 2(-2)^3 - 6(-2)^2 - 2(-2) + 1
  4. Calculate each term.

    (−2)4=16(-2)^4 = 16 −2(−2)3=−2(−8)=16-2(-2)^3 = -2(-8) = 16 −6(−2)2=−6(4)=−24-6(-2)^2 = -6(4) = -24 −2(−2)=4-2(-2) = 4 +1+1
  5. Sum the calculated terms to find the remainder.

    f(−2)=16+16−24+4+1f(-2) = 16 + 16 - 24 + 4 + 1 f(−2)=32−24+4+1f(-2) = 32 - 24 + 4 + 1 f(−2)=8+4+1f(-2) = 8 + 4 + 1 f(−2)=13f(-2) = 13

    The remainder is 13.

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