Simplify the following surd expression and give the answer in form of sqrt(k) where k is an integer. (3m)

Mathematics
Simplify the following surd expression and give the answer in form of sqrt(k) where k is an integer. (3m)

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Answer

46+36\frac{4\sqrt{6} + \sqrt{3}}{6}

Huu hapa ni usuluhisho wa kurahisisha usemi wa surd:

Hatua ya 1: Rahisisha kila neno kivyake. Kwa neno la kwanza, 83\sqrt{\frac{8}{3}}: 83=83=4×23=223\sqrt{\frac{8}{3}} = \frac{\sqrt{8}}{\sqrt{3}} = \frac{\sqrt{4 \times 2}}{\sqrt{3}} = \frac{2\sqrt{2}}{\sqrt{3}} Ili kuondoa surd kwenye denominator, zidisha namba na denominator kwa 3\sqrt{3}: 223×33=263\frac{2\sqrt{2}}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} = \frac{2\sqrt{6}}{3}

Hatua ya 2: Rahisisha neno la pili, 3227\frac{3}{2\sqrt{27}}: Kwanza, rahisiisha 27\sqrt{27}: 27=9×3=33\sqrt{27} = \sqrt{9 \times 3} = 3\sqrt{3} Badilisha hii kwenye neno: 3227=32(33)=363=123\frac{3}{2\sqrt{27}} = \frac{3}{2(3\sqrt{3})} = \frac{3}{6\sqrt{3}} = \frac{1}{2\sqrt{3}} Ili kuondoa surd kwenye denominator, zidisha namba na denominator kwa 3\sqrt{3}: 123×33=32×3=36\frac{1}{2\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{2 \times 3} = \frac{\sqrt{3}}{6}

Hatua ya 3: Jumlisha maneno yaliyorahisishwa. Sasa tuna maneno 263\frac{2\sqrt{6}}{3} na 36\frac{\sqrt{3}}{6}. Ili kuyajumlisha, tunahitaji denominator ya kawaida, ambayo ni 6. 263+36=26×23×2+36=466+36\frac{2\sqrt{6}}{3} + \frac{\sqrt{3}}{6} = \frac{2\sqrt{6} \times 2}{3 \times 2} + \frac{\sqrt{3}}{6} = \frac{4\sqrt{6}}{6} + \frac{\sqrt{3}}{6} =46+36= \frac{4\sqrt{6} + \sqrt{3}}{6}

Hatua ya 4: Angalia kama jibu linaweza kuandikwa katika fomu ya k\sqrt{k} ambapo kk ni namba kamili. Ikiwa usemi huu ni sawa na k\sqrt{k}, basi kuupiga mraba kutatoa kk: k=(46+36)2k = \left(\frac{4\sqrt{6} + \sqrt{3}}{6}\right)^2 k=(46)2+2(46)(3)+(3)262k = \frac{(4\sqrt{6})^2 + 2(4\sqrt{6})(\sqrt{3}) + (\sqrt{3})^2}{6^2} k=(16×6)+818+336k = \frac{(16 \times 6) + 8\sqrt{18} + 3}{36} k=96+8(32)+336k = \frac{96 + 8(3\sqrt{2}) + 3}{36} k=96+242+336k = \frac{96 + 24\sqrt{2} + 3}{36} k=99+24236k = \frac{99 + 24\sqrt{2}}{36} Kwa kuwa jibu lina neno la 2\sqrt{2}, ambalo ni namba isiyo na uwiano, kk haiwezi kuwa namba kamili. Hii inaonyesha kuwa usemi hauwezi kuandikwa katika fomu k\sqrt{k} ambapo kk ni namba kamili.

Kwa hivyo, jibu lililorahisishwa zaidi ni: \frac{4\sqrt{6 + \sqrt{3}}{6}} Tuma swali linalofuata 📸

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Huu hapa ni usuluhisho wa kurahisisha usemi wa surd: Hatua ya 1: Rahisisha kila neno kivyake.

Simplify the following surd expression and give the answer in form of sqrt(k) where k is an integer. (3m)
Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI Answer
Huu hapa ni usuluhisho wa kurahisisha usemi wa surd: Hatua ya 1: Rahisisha kila neno kivyake. Kwa neno la kwanza, sqrt((8)/(3)): sqrt((8)/(3)) = sqrt(8)sqrt(3) = sqrt(4 × 2)sqrt(3) = 2sqrt(2)sqrt(3) Ili kuondoa surd kwenye denominator, zidisha namba na denominator kwa sqrt(3): 2sqrt(2)sqrt(3) × sqrt(3)sqrt(3) = 2sqrt(6)3 Hatua ya 2: Rahisisha neno la pili, (3)/(2sqrt(27)): Kwanza, rahisiisha sqrt(27): sqrt(27) = sqrt(9 × 3) = 3sqrt(3) Badilisha hii kwenye neno: (3)/(2sqrt(27)) = (3)/(2(3sqrt(3))) = (3)/(6sqrt(3)) = (1)/(2sqrt(3)) Ili kuondoa surd kwenye denominator, zidisha namba na denominator kwa sqrt(3): (1)/(2sqrt(3)) × sqrt(3)sqrt(3) = sqrt(3)2 × 3 = sqrt(3)6 Hatua ya 3: Jumlisha maneno yaliyorahisishwa. Sasa tuna maneno 2sqrt(6)3 na sqrt(3)6. Ili kuyajumlisha, tunahitaji denominator ya kawaida, ambayo ni 6. 2sqrt(6)3 + sqrt(3)6 = 2sqrt(6) × 23 × 2 + sqrt(3)6 = 4sqrt(6)6 + sqrt(3)6 = 4sqrt(6) + sqrt(3)6 Hatua ya 4: Angalia kama jibu linaweza kuandikwa katika fomu ya sqrt(k) ambapo k ni namba kamili. Ikiwa usemi huu ni sawa na sqrt(k), basi kuupiga mraba kutatoa k: k = (4sqrt(6) + sqrt(3)6)^2 k = (4sqrt(6))^2 + 2(4sqrt(6))(sqrt(3)) + (sqrt(3))^26^2 k = (16 × 6) + 8sqrt(18) + 336 k = 96 + 8(3sqrt(2)) + 336 k = 96 + 24sqrt(2) + 336 k = 99 + 24sqrt(2)36 Kwa kuwa jibu lina neno la sqrt(2), ambalo ni namba isiyo na uwiano, k haiwezi kuwa namba kamili. Hii inaonyesha kuwa usemi hauwezi kuandikwa katika fomu sqrt(k) ambapo k ni namba kamili. Kwa hivyo, jibu lililorahisishwa zaidi ni: 4sqrt(6) + sqrt(3)6 Tuma swali linalofuata 📸